基于两个输入-日期（日历中的任何日期）和日期期限（年，月或周），结果应汇总数据：
请原谅我的长篇文章，但没有办法解释得太短，
例如；如果将@period指定为 YEAR ，则它应基于该年的所有月份汇总结果，而对于缺少的月份，则应为0，
当@period指定为 MONTH 时，则应基于该年该月特定月份的所有日期汇总结果，而对于缺少的日期则应为0，
当@period以 WEEK 的形式给出时，则应基于该特定月份和年份的特定一周中的天（给定周的第一天和最后一天之间）汇总结果，并且如果缺少工作日，则应为0，
当@period指定为 DAY 时，则应该基于给定日期的小时数（0小时至23小时）汇总结果，而缺少的小时应为0。
以下是示例数据：
CREATE TABLE [dbo].[transferTable](
[ID] [bigint] IDENTITY(1000,1) NOT NULL,
[transferDateTime] [datetime] NOT NULL,
[transferAmount] [money] NOT NULL
) ON [PRIMARY]
GO
SET IDENTITY_INSERT [dbo].[transferTable] ON
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1000, CAST(0x0000AA2C0110897B AS DateTime), 10.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1001, CAST(0x0000AA2D00F0AA50 AS DateTime), 151.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1002, CAST(0x0000A8850110897B AS DateTime), 10.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1003, CAST(0x0000AA0E0121043B AS DateTime), 151.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1005, CAST(0x0000AA4B01220A00 AS DateTime), 70.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1006, CAST(0x0000AA4A013284C0 AS DateTime), 75.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1007, CAST(0x0000AA4401537A40 AS DateTime), 85.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1008, CAST(0x0000AA4F002AD8C0 AS DateTime), 20.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1009, CAST(0x0000AA4F003B5380 AS DateTime), 25.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1010, CAST(0x0000AA4F005C4900 AS DateTime), 45.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1011, CAST(0x0000AA4F005C4900 AS DateTime), 14.0000)
GO
INSERT [dbo].[transferTable] ([ID], [transferDateTime], [transferAmount]) VALUES (1012, CAST(0x0000A8C4006CC3C0 AS DateTime), 66.0000)
GO
SET IDENTITY_INSERT [dbo].[transferTable] OFF
GO
实际代码：
DECLARE @calenderDate DATETIME2(0) = '2019-04-16 05:00'
DECLARE @period varchar(10) = 'year'
DECLARE @year varchar(10) = DATEPART(YEAR,@calenderDate)
DECLARE @month varchar(10)= DATEPART(MONTH,@calenderDate)
DECLARE @week varchar(10) = DATEPART(WEEK,@calenderDate)
DECLARE @hour varchar(10) = DATEPART(HOUR,@calenderDate)
select case when @period = 'YEAR' then DATEPART(MONTH,transferDateTime)
when @period = 'MONTH' then DATEPART(DAY,transferDateTime)
when @period = 'WEEK' then DATEPART(WEEK,transferDateTime)
when @period = 'DAY' then DATEPART(HOUR,transferDateTime)
end as period,
COUNT (t.transferAmount) as volOfTxns,
SUM (t.transferAmount) as ValueOfTxns
from transferTable t
where
(
(@period = 'YEAR' AND DATEPART(YEAR,t.transferDateTime) = @year)
OR (@period = 'MONTH' AND ( DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month))
OR (@period = 'WEEK' AND (DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month) AND DATEPART(WEEK,t.transferDateTime) = @week)
OR (@period = 'DAY' AND (DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month) AND DATEPART(WEEK,t.transferDateTime) = @week AND DATEPART(HOUR,t.transferDateTime) = @hour)
)
group by case when @period = 'YEAR' then DATEPART(MONTH,transferDateTime)
when @period = 'MONTH' then DATEPART(DAY,transferDateTime)
when @period = 'WEEK' then DATEPART(WEEK,transferDateTime)
when @period = 'DAY' then DATEPART(HOUR,transferDateTime)
end
问题1-我希望丢失的数据应显示为0。
例如，如果输入如下所示；
DECLARE @calenderDate DATETIME2(0) = '2019-03-16 05:00'
DECLARE @period varchar(10) = 'year'
实际结果是：
period volOfTxns ValueOfTxns
3 1 151.00
4 2 161.00
5 7 334.00
预期结果是：还显示该年中缺少的月份，但期间字段中的值为0（此处的期间字段表示月份）。
period volOfTxns ValueOfTxns
1 0 0
2 0 0
3 1 151
4 2 161
5 7 334
6 0 0
7 0 0
8 0 0
9 0 0
10 0 0
11 0 0
12 0 0
同样，如果 @period ='month'，则应在期间字段中显示日期1到31（或基于该月的1到30）（对于缺失的天，它应该显示0）期间字段代表日期）。
同样，如果 @period ='week'，则应在期间字段中显示星期日至星期六的工作日（对于缺少的工作日，则应显示0）（此处的期间字段代表工作日）。
同样，如果 @period ='day'，则应在期间字段中显示00到23小时（缺少的小时应显示0）（此处的期间字段表示小时）。
答案 0 :(得分：2)
使用rangeAB（下面的T-SQL代码）很容易。
将查询转换为子查询。使用rangeAB生成所需的数字（例如，选择YEAR时为1-12）。然后将您的子查询LEFT JOIN到rangeAB查询。
SELECT
[period] = r.RN,
volOfTxns = ISNULL(t.volOfTxns,0),
ValueOfTxns = ISNULL(t.ValueOfTxns,0)
FROM dbo.rangeAB(1,12,1,1) AS r
LEFT JOIN
(
select case when @period = 'YEAR' then DATEPART(MONTH,transferDateTime)
when @period = 'MONTH' then DATEPART(DAY,transferDateTime)
when @period = 'WEEK' then DATEPART(WEEK,transferDateTime)
when @period = 'DAY' then DATEPART(HOUR,transferDateTime)
end as period,
COUNT (t.transferAmount) as volOfTxns,
SUM (t.transferAmount) as ValueOfTxns
from transferTable AS t
where
(
(@period = 'YEAR' AND DATEPART(YEAR,t.transferDateTime) = @year)
OR (@period = 'MONTH' AND ( DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month))
OR (@period = 'WEEK' AND (DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month) AND DATEPART(WEEK,t.transferDateTime) = @week)
OR (@period = 'DAY' AND (DATEPART(YEAR,t.transferDateTime) = @year AND DATEPART(MONTH,t.transferDateTime) = @month) AND DATEPART(WEEK,t.transferDateTime) = @week AND DATEPART(HOUR,t.transferDateTime) = @hour)
)
group by case when @period = 'YEAR' then DATEPART(MONTH,transferDateTime)
when @period = 'MONTH' then DATEPART(DAY,transferDateTime)
when @period = 'WEEK' then DATEPART(WEEK,transferDateTime)
when @period = 'DAY' then DATEPART(HOUR,transferDateTime)
END
) AS t ON r.RN = t.[period];
返回：
period volOfTxns ValueOfTxns
-------------------- ----------- ---------------------
1 0 0.00
2 0 0.00
3 1 151.00
4 2 161.00
5 7 334.00
6 0 0.00
7 0 0.00
8 0 0.00
9 0 0.00
10 0 0.00
11 0 0.00
12 0 0.00
要处理多个句点，您可以将rangeAB（1,12,1,1）中的数字12更改为表达式/案例语句，其中较高的数字基于您用于其他类型的句点的逻辑。
范围AB代码：
CREATE FUNCTION dbo.rangeAB
(
@low BIGINT,
@high BIGINT,
@gap BIGINT,
@row1 BIT
)
/****************************************************************************************
[Purpose]:
Creates up to 531,441,000,000 sequentia1 integers numbers beginning with @low and ending
with @high. Used to replace iterative methods such as loops, cursors and recursive CTEs
to solve SQL problems. Based on Itzik Ben-Gan's getnums function with some tweeks and
enhancements and added functionality. The logic for getting rn to begin at 0 or 1 is
based comes from Jeff Moden's fnTally function.
The name range because it's similar to clojure's range function. The name "rangeAB" as
used because "range" is a reserved SQL keyword.
[Author]: Alan Burstein
[Compatibility]:
SQL Server 2008+ and Azure SQL Database
[Syntax]:
SELECT r.RN, r.OP, r.N1, r.N2
FROM dbo.rangeAB(@low,@high,@gap,@row1) AS r;
[Parameters]:
@low = a bigint that represents the lowest value for n1.
@high = a bigint that represents the highest value for n1.
@gap = a bigint that represents how much n1 and n2 will increase each row; @gap also
represents the difference between n1 and n2.
@row1 = a bit that represents the first value of rn. When @row = 0 then rn begins
at 0, when @row = 1 then rn will begin at 1.
[Returns]:
Inline Table Valued Function returns:
rn = bigint; a row number that works just like T-SQL ROW_NUMBER() except that it can
start at 0 or 1 which is dictated by @row1.
op = bigint; returns the "opposite number that relates to rn. When rn begins with 0 and
ends with 10 then 10 is the opposite of 0, 9 the opposite of 1, etc. When rn begins
with 1 and ends with 5 then 1 is the opposite of 5, 2 the opposite of 4, etc...
n1 = bigint; a sequential number starting at the value of @low and incrimentingby the
value of @gap until it is less than or equal to the value of @high.
n2 = bigint; a sequential number starting at the value of @low+@gap and incrimenting
by the value of @gap.
[Dependencies]:
N/A
[Developer Notes]:
1. The lowest and highest possible numbers returned are whatever is allowable by a
bigint. The function, however, returns no more than 531,441,000,000 rows (8100^3).
2. @gap does not affect rn, rn will begin at @row1 and increase by 1 until the last row
unless its used in a query where a filter is applied to rn.
3. @gap must be greater than 0 or the function will not return any rows.
4. Keep in mind that when @row1 is 0 then the highest row-number will be the number of
rows returned minus 1
5. If you only need is a sequential set beginning at 0 or 1 then, for best performance
use the RN column. Use N1 and/or N2 when you need to begin your sequence at any
number other than 0 or 1 or if you need a gap between your sequence of numbers.
6. Although @gap is a bigint it must be a positive integer or the function will
not return any rows.
7. The function will not return any rows when one of the following conditions are true:
* any of the input parameters are NULL
* @high is less than @low
* @gap is not greater than 0
To force the function to return all NULLs instead of not returning anything you can
add the following code to the end of the query:
UNION ALL
SELECT NULL, NULL, NULL, NULL
WHERE NOT (@high&@low&@gap&@row1 IS NOT NULL AND @high >= @low AND @gap > 0)
This code was excluded as it adds a ~5% performance penalty.
8. There is no performance penalty for sorting by rn ASC; there is a large performance
penalty for sorting in descending order WHEN @row1 = 1; WHEN @row1 = 0
If you need a descending sort the use op in place of rn then sort by rn ASC.
Best Practices:
--===== 1. Using RN (rownumber)
-- (1.1) The best way to get the numbers 1,2,3...@high (e.g. 1 to 5):
SELECT RN FROM dbo.rangeAB(1,5,1,1);
-- (1.2) The best way to get the numbers 0,1,2...@high-1 (e.g. 0 to 5):
SELECT RN FROM dbo.rangeAB(0,5,1,0);
--===== 2. Using OP for descending sorts without a performance penalty
-- (2.1) The best way to get the numbers 5,4,3...@high (e.g. 5 to 1):
SELECT op FROM dbo.rangeAB(1,5,1,1) ORDER BY rn ASC;
-- (2.2) The best way to get the numbers 0,1,2...@high-1 (e.g. 5 to 0):
SELECT op FROM dbo.rangeAB(1,6,1,0) ORDER BY rn ASC;
--===== 3. Using N1
-- (3.1) To begin with numbers other than 0 or 1 use N1 (e.g. -3 to 3):
SELECT N1 FROM dbo.rangeAB(-3,3,1,1);
-- (3.2) ROW_NUMBER() is built in. If you want a ROW_NUMBER() include RN:
SELECT RN, N1 FROM dbo.rangeAB(-3,3,1,1);
-- (3.3) If you wanted a ROW_NUMBER() that started at 0 you would do this:
SELECT RN, N1 FROM dbo.rangeAB(-3,3,1,0);
--===== 4. Using N2 and @gap
-- (4.1) To get 0,10,20,30...100, set @low to 0, @high to 100 and @gap to 10:
SELECT N1 FROM dbo.rangeAB(0,100,10,1);
-- (4.2) Note that N2=N1+@gap; this allows you to create a sequence of ranges.
-- For example, to get (0,10),(10,20),(20,30).... (90,100):
SELECT N1, N2 FROM dbo.rangeAB(0,90,10,1);
-- (4.3) Remember that a rownumber is included and it can begin at 0 or 1:
SELECT RN, N1, N2 FROM dbo.rangeAB(0,90,10,1);
[Examples]:
--===== 1. Generating Sample data (using rangeAB to create "dummy rows")
-- The query below will generate 10,000 ids and random numbers between 50,000 and 500,000
SELECT
someId = r.rn,
someNumer = ABS(CHECKSUM(NEWID())%450000)+50001
FROM rangeAB(1,10000,1,1) r;
--===== 2. Create a series of dates; rn is 0 to include the first date in the series
DECLARE @startdate DATE = '20180101', @enddate DATE = '20180131';
SELECT r.rn, calDate = DATEADD(dd, r.rn, @startdate)
FROM dbo.rangeAB(1, DATEDIFF(dd,@startdate,@enddate),1,0) r;
GO
--===== 3. Splitting (tokenizing) a string with fixed sized items
-- given a delimited string of identifiers that are always 7 characters long
DECLARE @string VARCHAR(1000) = 'A601225,B435223,G008081,R678567';
SELECT
itemNumber = r.rn, -- item's ordinal position
itemIndex = r.n1, -- item's position in the string (it's CHARINDEX value)
item = SUBSTRING(@string, r.n1, 7) -- item (token)
FROM dbo.rangeAB(1, LEN(@string), 8,1) r;
GO
--===== 4. Splitting (tokenizing) a string with random delimiters
DECLARE @string VARCHAR(1000) = 'ABC123,999F,XX,9994443335';
SELECT
itemNumber = ROW_NUMBER() OVER (ORDER BY r.rn), -- item's ordinal position
itemIndex = r.n1+1, -- item's position in the string (it's CHARINDEX value)
item = SUBSTRING
(
@string,
r.n1+1,
ISNULL(NULLIF(CHARINDEX(',',@string,r.n1+1),0)-r.n1-1, 8000)
) -- item (token)
FROM dbo.rangeAB(0,DATALENGTH(@string),1,1) r
WHERE SUBSTRING(@string,r.n1,1) = ',' OR r.n1 = 0;
-- logic borrowed from: http://www.sqlservercentral.com/articles/Tally+Table/72993/
--===== 5. Grouping by a weekly intervals
-- 5.1. how to create a series of start/end dates between @startDate & @endDate
DECLARE @startDate DATE = '1/1/2015', @endDate DATE = '2/1/2015';
SELECT
WeekNbr = r.RN,
WeekStart = DATEADD(DAY,r.N1,@StartDate),
WeekEnd = DATEADD(DAY,r.N2-1,@StartDate)
FROM dbo.rangeAB(0,datediff(DAY,@StartDate,@EndDate),7,1) r;
GO
-- 5.2. LEFT JOIN to the weekly interval table
BEGIN
DECLARE @startDate datetime = '1/1/2015', @endDate datetime = '2/1/2015';
-- sample data
DECLARE @loans TABLE (loID INT, lockDate DATE);
INSERT @loans SELECT r.rn, DATEADD(dd, ABS(CHECKSUM(NEWID())%32), @startDate)
FROM dbo.rangeAB(1,50,1,1) r;
-- solution
SELECT
WeekNbr = r.RN,
WeekStart = dt.WeekStart,
WeekEnd = dt.WeekEnd,
total = COUNT(l.lockDate)
FROM dbo.rangeAB(0,datediff(DAY,@StartDate,@EndDate),7,1) r
CROSS APPLY (VALUES (
CAST(DATEADD(DAY,r.N1,@StartDate) AS DATE),
CAST(DATEADD(DAY,r.N2-1,@StartDate) AS DATE))) dt(WeekStart,WeekEnd)
LEFT JOIN @loans l ON l.lockDate BETWEEN dt.WeekStart AND dt.WeekEnd
GROUP BY r.RN, dt.WeekStart, dt.WeekEnd ;
END;
--===== 6. Identify the first vowel and last vowel in a along with their positions
DECLARE @string VARCHAR(200) = 'This string has vowels';
SELECT TOP(1) position = r.rn, letter = SUBSTRING(@string,r.rn,1)
FROM dbo.rangeAB(1,LEN(@string),1,1) r
WHERE SUBSTRING(@string,r.rn,1) LIKE '%[aeiou]%'
ORDER BY r.rn;
-- To avoid a sort in the execution plan we'll use op instead of rn
SELECT TOP(1) position = r.op, letter = SUBSTRING(@string,r.op,1)
FROM dbo.rangeAB(1,LEN(@string),1,1) r
WHERE SUBSTRING(@string,r.rn,1) LIKE '%[aeiou]%'
ORDER BY r.rn;
---------------------------------------------------------------------------------------
[Revision History]:
Rev 00 - 20140518 - Initial Development - Alan Burstein
Rev 01 - 20151029 - Added 65 rows to make L1=465; 465^3=100.5M. Updated comment section
- Alan Burstein
Rev 02 - 20180613 - Complete re-design including opposite number column (op)
Rev 03 - 20180920 - Added additional CROSS JOIN to L2 for 530B rows max - Alan Burstein
****************************************************************************************/
RETURNS TABLE WITH SCHEMABINDING AS RETURN
WITH L1(N) AS
(
SELECT 1
FROM (VALUES
(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),
(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),
(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),
(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),(0),
(0),(0)) T(N) -- 90 values
),
L2(N) AS (SELECT 1 FROM L1 a CROSS JOIN L1 b CROSS JOIN L1 c),
iTally AS (SELECT rn = ROW_NUMBER() OVER (ORDER BY (SELECT 1)) FROM L2 a CROSS JOIN L2 b)
SELECT
r.RN,
r.OP,
r.N1,
r.N2
FROM
(
SELECT
RN = 0,
OP = (@high-@low)/@gap,
N1 = @low,
N2 = @gap+@low
WHERE @row1 = 0
UNION ALL -- COALESCE required in the TOP statement below for error handling purposes
SELECT TOP (ABS((COALESCE(@high,0)-COALESCE(@low,0))/COALESCE(@gap,0)+COALESCE(@row1,1)))
RN = i.rn,
OP = (@high-@low)/@gap+(2*@row1)-i.rn,
N1 = (i.rn-@row1)*@gap+@low,
N2 = (i.rn-(@row1-1))*@gap+@low
FROM iTally AS i
ORDER BY i.rn
) AS r
WHERE @high&@low&@gap&@row1 IS NOT NULL AND @high >= @low AND @gap > 0;
GO
答案 1 :(得分：2)
我认为本周的处理方式不正确，其结果将不同于您查询的结果，因此，我将按CTE构建时间段，将其与您的数据结合起来，并进行一些修改。
我测试了“ YEAR”，“ MONTH”，“ WEEK”，“ DAY”的所有时段，并显示了结果。
我的长查询（基于您的查询）如下：-
DECLARE @calenderDate DATETIME2(0) = '2019-05-16 05:00'
DECLARE @period varchar(10) = 'YEAR' -- 'MONTH' or 'WEEK''DAY'
--find the start and end for each period
Declare @PeriodStart datetime,@PeriodEnd datetime
select @PeriodStart=case when @period = 'YEAR' then cast(cast(year(@calenderDate) as varchar(4))+'-01-01' as datetime)
when @period = 'MONTH' then cast(cast(year(@calenderDate) as varchar(4))+'-'+cast(Month(@calenderDate) as varchar(2))+'-01' as datetime)
when @period = 'WEEK' then DATEADD(dd, -(DATEPART(dw, cast(@calenderDate as date))-1), cast(@calenderDate as date))
when @period = 'DAY' then cast(cast(year(@calenderDate) as varchar(4))+'-'+cast(month(@calenderDate) as varchar(2))+'-'+cast(day(@calenderDate)as varchar(2)) as datetime) end
select @PeriodEnd=case when @period = 'YEAR' then dateadd(MILLISECOND,-3,dateadd(month,12,@PeriodStart))
when @period = 'MONTH' then dateadd(MILLISECOND,-3,dateadd(month,1,@PeriodStart))
when @period = 'WEEK' then dateadd(MILLISECOND,-3,dateadd(day,7,@PeriodStart))
when @period = 'DAY' then dateadd(MILLISECOND,-3,dateadd(hour,24,@PeriodStart)) end
;with PeriodYear as (
select @PeriodStart [Period]
union all
select dateadd(month,1,PeriodYear.[Period]) from PeriodYear where dateadd(month,1,PeriodYear.[Period])<=@PeriodEnd
),PeriodMonth as (
select @PeriodStart [Period]
union all
select dateadd(DAY,1,PeriodMonth.[Period]) from PeriodMonth where dateadd(DAY,1,PeriodMonth.[Period])<=@PeriodEnd
),PeriodWeek as (
select @PeriodStart [Period]
union all
select dateadd(DAY,1,PeriodWeek.[Period]) from PeriodWeek where dateadd(DAY,1,PeriodWeek.[Period])<=@PeriodEnd
),PeriodDay as (
select @PeriodStart [Period]
union all
select dateadd(hour,1,PeriodDay.[Period]) from PeriodDay where dateadd(hour,1,PeriodDay.[Period])<=@PeriodEnd
),GroupData as (
select case
when @period = 'YEAR' then cast(cast(DATEPART(year,min(transferDateTime)) as varchar(4))+'-'+cast(DATEPART(MONTH,min(transferDateTime)) as varchar(2))+'-01' as datetime)
when @period = 'MONTH' then cast(cast(min(transferDateTime) as date) as datetime)
when @period = 'WEEK' then cast(cast(min(transferDateTime) as date) as datetime)
when @period = 'DAY' then dateadd(hour,DATEPART(HOUR,min(transferDateTime)),cast(cast(min(transferDateTime) as date) as datetime))
end as [period],
COUNT (t.transferAmount) as volOfTxns,
SUM (t.transferAmount) as ValueOfTxns
from transferTable t
where
t.transferDateTime between @PeriodStart and @PeriodEnd
group by case when @period = 'YEAR' then DATEPART(MONTH,transferDateTime)
when @period = 'MONTH' then DATEPART(DAY,transferDateTime)
when @period = 'WEEK' then DATEPART(DAY,transferDateTime)
when @period = 'DAY' then DATEPART(HOUR,transferDateTime)
end
),RangeDataSet as (
select * from PeriodYear where @period = 'YEAR' union all
select * from PeriodMonth where @period = 'MONTH' union all
select * from PeriodWeek where @period = 'WEEK' union all
select * from PeriodDay where @period = 'DAY'
)
select RangeDataSet.[Period] [PeriodDate]
,case when @period = 'YEAR' then cast(DATEPART(MONTH,RangeDataSet.[Period]) as varchar(50))
when @period = 'MONTH' then cast(DATEPART(DAY,RangeDataSet.[Period]) as varchar(50))
when @period = 'WEEK' then cast(datename(WEEKDAY,RangeDataSet.[Period]) as varchar(50))
when @period = 'DAY' then cast(Right('00' + cast(DATEPART(HOUR,RangeDataSet.[Period]) as varchar(2)),2) as varchar(50))+' hrs'
end [Period]
,isnull(volOfTxns,0) volOfTxns,isnull(ValueOfTxns,0) ValueOfTxns from RangeDataSet
left outer join GroupData on GroupData.[Period]=RangeDataSet.[Period]
每种期间类型的结果
年份
PeriodDate Period volOfTxns ValueOfTxns
2019-01-01 00:00:00.000 1 0 0.00
2019-02-01 00:00:00.000 2 0 0.00
2019-03-01 00:00:00.000 3 1 151.00
2019-04-01 00:00:00.000 4 2 161.00
2019-05-01 00:00:00.000 5 7 334.00
2019-06-01 00:00:00.000 6 0 0.00
2019-07-01 00:00:00.000 7 0 0.00
2019-08-01 00:00:00.000 8 0 0.00
2019-09-01 00:00:00.000 9 0 0.00
2019-10-01 00:00:00.000 10 0 0.00
2019-11-01 00:00:00.000 11 0 0.00
2019-12-01 00:00:00.000 12 0 0.00
一个月
PeriodDate Period volOfTxns ValueOfTxns
2019-05-01 00:00:00.000 1 0 0.00
2019-05-02 00:00:00.000 2 0 0.00
2019-05-03 00:00:00.000 3 0 0.00
2019-05-04 00:00:00.000 4 0 0.00
2019-05-05 00:00:00.000 5 1 85.00
2019-05-06 00:00:00.000 6 0 0.00
2019-05-07 00:00:00.000 7 0 0.00
2019-05-08 00:00:00.000 8 0 0.00
2019-05-09 00:00:00.000 9 0 0.00
2019-05-10 00:00:00.000 10 0 0.00
2019-05-11 00:00:00.000 11 1 75.00
2019-05-12 00:00:00.000 12 1 70.00
2019-05-13 00:00:00.000 13 0 0.00
2019-05-14 00:00:00.000 14 0 0.00
2019-05-15 00:00:00.000 15 0 0.00
2019-05-16 00:00:00.000 16 4 104.00
2019-05-17 00:00:00.000 17 0 0.00
2019-05-18 00:00:00.000 18 0 0.00
2019-05-19 00:00:00.000 19 0 0.00
2019-05-20 00:00:00.000 20 0 0.00
2019-05-21 00:00:00.000 21 0 0.00
2019-05-22 00:00:00.000 22 0 0.00
2019-05-23 00:00:00.000 23 0 0.00
2019-05-24 00:00:00.000 24 0 0.00
2019-05-25 00:00:00.000 25 0 0.00
2019-05-26 00:00:00.000 26 0 0.00
2019-05-27 00:00:00.000 27 0 0.00
2019-05-28 00:00:00.000 28 0 0.00
2019-05-29 00:00:00.000 29 0 0.00
2019-05-30 00:00:00.000 30 0 0.00
2019-05-31 00:00:00.000 31 0 0.00
对于显示7天的周
PeriodDate Period volOfTxns ValueOfTxns
2019-05-12 00:00:00.000 Sunday 1 70.00
2019-05-13 00:00:00.000 Monday 0 0.00
2019-05-14 00:00:00.000 Tuesday 0 0.00
2019-05-15 00:00:00.000 Wednesday 0 0.00
2019-05-16 00:00:00.000 Thursday 4 104.00
2019-05-17 00:00:00.000 Friday 0 0.00
2019-05-18 00:00:00.000 Saturday 0 0.00
每天
PeriodDate Period volOfTxns ValueOfTxns
2019-05-16 00:00:00.000 00 hrs 0 0.00
2019-05-16 01:00:00.000 01 hrs 0 0.00
2019-05-16 02:00:00.000 02 hrs 1 20.00
2019-05-16 03:00:00.000 03 hrs 1 25.00
2019-05-16 04:00:00.000 04 hrs 0 0.00
2019-05-16 05:00:00.000 05 hrs 2 59.00
2019-05-16 06:00:00.000 06 hrs 0 0.00
2019-05-16 07:00:00.000 07 hrs 0 0.00
2019-05-16 08:00:00.000 08 hrs 0 0.00
2019-05-16 09:00:00.000 09 hrs 0 0.00
2019-05-16 10:00:00.000 10 hrs 0 0.00
2019-05-16 11:00:00.000 11 hrs 0 0.00
2019-05-16 12:00:00.000 12 hrs 0 0.00
2019-05-16 13:00:00.000 13 hrs 0 0.00
2019-05-16 14:00:00.000 14 hrs 0 0.00
2019-05-16 15:00:00.000 15 hrs 0 0.00
2019-05-16 16:00:00.000 16 hrs 0 0.00
2019-05-16 17:00:00.000 17 hrs 0 0.00
2019-05-16 18:00:00.000 18 hrs 0 0.00
2019-05-16 19:00:00.000 19 hrs 0 0.00
2019-05-16 20:00:00.000 20 hrs 0 0.00
2019-05-16 21:00:00.000 21 hrs 0 0.00
2019-05-16 22:00:00.000 22 hrs 0 0.00
2019-05-16 23:00:00.000 23 hrs 0 0.00
希望这会有所帮助。
答案 2 :(得分：1)
这是解决同一问题的一种方法。汇总提交分组而不是将日期模式作为参数提交，然后根据传入的参数有条件地进行求和，而不是按组进行分组显示分层的所有日期排列。表示年份优先于月份，月份优先于一天，依此类推。
为防止出现空值，我合并了日期部分，这也迫使我在order by子句中添加了一些跳格，以便正确地显示日期。
最后一点，@ calendarday参数用于提供> = where子句，这意味着该结果集将显示5月的交易，但是您可以根据需要进行切换，这意味着您对数据有整体的了解在此之前。
CREATE TABLE #transferTable(
[ID] [bigint] IDENTITY(1000,1) NOT NULL,
[transferDateTime] [datetime] NOT NULL,
[transferAmount] [money] NOT NULL
) ON [PRIMARY]
GO
SET IDENTITY_INSERT #transfertable ON
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1000, CAST(0x0000AA2C0110897B AS DateTime), 10.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1001, CAST(0x0000AA2D00F0AA50 AS DateTime), 151.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1002, CAST(0x0000A8850110897B AS DateTime), 10.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1003, CAST(0x0000AA0E0121043B AS DateTime), 151.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1005, CAST(0x0000AA4B01220A00 AS DateTime), 70.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1006, CAST(0x0000AA4A013284C0 AS DateTime), 75.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1007, CAST(0x0000AA4401537A40 AS DateTime), 85.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1008, CAST(0x0000AA4F002AD8C0 AS DateTime), 20.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1009, CAST(0x0000AA4F003B5380 AS DateTime), 25.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1010, CAST(0x0000AA4F005C4900 AS DateTime), 45.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1011, CAST(0x0000AA4F005C4900 AS DateTime), 14.0000)
GO
INSERT #transfertable ([ID], [transferDateTime], [transferAmount]) VALUES (1012, CAST(0x0000A8C4006CC3C0 AS DateTime), 66.0000)
GO
SET IDENTITY_INSERT #transfertable OFF
GO
DECLARE @calenderDate DATETIME2(0) = '2019-04-16 05:00'
DECLARE @year varchar(10) = DATEPART(YEAR,@calenderDate)
DECLARE @month varchar(10)= DATEPART(MONTH,@calenderDate)
DECLARE @week varchar(10) = DATEPART(WEEK,@calenderDate)
DECLARE @hour varchar(10) = DATEPART(HOUR,@calenderDate)
select coalesce(cast(DATEPART(YEAR,transferDateTime)as nvarchar(16)),'Year total') as year_period,
coalesce(cast(DATEPART(MONTH,transferDateTime) as nvarchar(16)),'Month total') as month_period,
coalesce(cast(DATEPART(WEEK,transferDateTime)as nvarchar(16)),'week total') as week_period,
coalesce(cast(DATEPART(DAY,transferDateTime) as nvarchar(16)),'day total') as day_period,
count(t.transferAmount) as volofTxns, coalesce(sum(t.transferAmount),0) as ValueofTxns
from #transferTable t where t.transferDateTime>=@calenderDate
group by rollup (DATEPART(YEAR,transferDateTime), DATEPART(MONTH,transferDateTime),
DATEPART(WEEK,transferDateTime),DATEPART(DAY,transferDateTime))
order by year_period, month_period, week_period,
case when datepart(day,transferdatetime) = '1' then 1 when datepart(day,transferdatetime) = '2' then 2 when datepart(day,transferdatetime) = '3' then 3 when datepart(day,transferdatetime) = '4' then 4 when datepart(day,transferdatetime) = '5' then 5 when datepart(day,transferdatetime) = '6' then 6
when datepart(day,transferdatetime) = '7' then 7 when datepart(day,transferdatetime) = '8' then 8 when datepart(day,transferdatetime) = '9' then 9 when datepart(day,transferdatetime) = '10' then 10 when datepart(day,transferdatetime) = '11' then 11 when datepart(day,transferdatetime) = '12' then 12
when datepart(day,transferdatetime) = '13' then 13 when datepart(day,transferdatetime) = '14' then 14 when datepart(day,transferdatetime) = '15' then 15 when datepart(day,transferdatetime) = '16' then 16 when datepart(day,transferdatetime) = '17' then 17 when datepart(day,transferdatetime) = '18' then 18
when datepart(day,transferdatetime) = '19' then 19 when datepart(day,transferdatetime) = '20' then 20 when datepart(day,transferdatetime) = '21' then 21 when datepart(day,transferdatetime) = '22' then 22 when datepart(day,transferdatetime) = '23' then 23 when datepart(day,transferdatetime) = '24' then 24
when datepart(day,transferdatetime) = '25' then 25 when datepart(day,transferdatetime) = '26' then 26 when datepart(day,transferdatetime) = '27' then 27 when datepart(day,transferdatetime) = '28' then 28 when datepart(day,transferdatetime) = '29' then 29 when datepart(day,transferdatetime) = '30' then 30
when datepart(day,transferdatetime) = '31' then 31 else 32 end;
drop table #transferTable;
答案 3 :(得分：1)
以下内容使用递归CTE。我只准备了年和月的脚本。如果这对您有效，则只需添加其他条件：
DECLARE @calenderDate DATETIME2(0) = '2019-03-16 05:00'
Declare @day1Month Date = Cast(Year(@calenderDate) As Char(4)) + '-' + Cast(Month(@calenderDate) As Char(2)) + '-01'
Declare @Year Int = Year(@calenderDate)
Declare @Month Int = Month(@calenderDate)
DECLARE @period varchar(10) = 'Year'
Declare @periodlst Table (period Int)
------------------------------------------->获取期间列表
If @period = 'Year' --List numbers 1 to 12
Insert @periodlst Select * From ( Values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12) ) p(period);
Else If @period = 'Month' --List numbers 1 to end of month
with numcte AS
(
SELECT 1 [num]
UNION all
SELECT [num] + 1 FROM numcte WHERE [num] < (Select datediff(day, @day1Month, dateadd(month, 1, @day1Month)))
)
Insert @periodlst Select * FROM numcte
-------------------------------------------------- --->递归CTE
;With cte As
(
Select
Case When @period = 'Year' Then Month(transferDateTime)
When @period = 'Month' Then Day(transferDateTime)
End As period
,*
From transferTable Where
(@period = 'Year' And Year(transferDateTime) = @Year) Or
(@period = 'Month' And Year(transferDateTime) = @Year And Month(transferDateTime) = @Month)
)
, cte1 As
(
Select * From @periodlst
)
Select
cte1.period As periods,
Count(TransferAmount) As volOfTxns,
IsNull(Sum(TransferAmount),0) As valueOfTxns
From cte1 Left Join cte On
cte.period = cte1.period
Group By cte1.period