Question

我正在运行时创建数据库和表。当我执行代码时，它正在创建数据库，而不是表。它将引发错误：“未选择数据库”；请引导我。

$sql = "CREATE DATABASE $db_name";
if ($this->db->query($sql) === TRUE) {
    $errors = [];

    $table1 = "CREATE TABLE `login_detail` (
                `id` int(100)  UNSIGNED AUTO_INCREMENT PRIMARY KEY,
                `employee_id` varchar(100) NOT NULL,
                `full_name` varchar(150) NOT NULL,
                `password` varchar(100) NOT NULL,
                `role` varchar(50) NOT NULL,
                `profile_image` varchar(255) NOT NULL,
                `status` varchar(100) NOT NULL DEFAULT '1')";

    $table2 = "INSERT INTO `login_detail` 
                        (`id`, `employee_id`, `full_name`, 
                        `password`, `role`, `profile_image`, `status`) 
                VALUES (1, 'admin', 'admin', 
                        '21232f297a57a5a743894a0e4a801fc3', 'admin', 
                        'uploads/profiles/admin.jpg', '1')";
    $tables = [$table1, $table2];

    foreach($tables as $k => $sql1){
        $query = $this->db->query($sql1);
        if(!$query)
            $errors[] = "Table $k : Creation failed ($this->db->error)";
        else
            $errors[] = "Table $k : Creation done";
    }

    foreach($errors as $msg) {
        echo "$msg <br>";
    }
} else {
    echo "Error creating database: " . $this->db->error;
}

Answer 1

您还应该告诉脚本使用数据库（请参见https://dev.mysql.com/doc/refman/5.7/en/use.html）

$sql = "CREATE DATABASE $db_name";
if ($this->db->query($sql) === TRUE) {
  $sqlUse = "USE $db_name";
  if ($this->db->query($sqlUse) === TRUE) {
    ...
  }

如何在使用Codeigniter创建表时选择数据库？

1 个答案: