Question

我正在尝试将数组转换为json，但没有得到我想要的确切结果。

在这里

<?php
      $result=array();
      $result[status]=1;
      $data=array(
                array("ucode" => "123","name" => "abc","lname" => "xyz"),
                array("ucode" => "431","name" => "cdb","lname" => "zsa")
              );
      foreach($data as $res){ 
          $data=array();
           $data[ucode]=$res['ucode'];
           $data[name]= $res['name'];
           $data[lname]= $res['lname'];
           $result[content]=$data;
        }

echo $res=json_encode($result);

?>

实际结果：

{"status":1,"content":{"ucode":"431","name":"cdb","lname":"zsa"}}

我的预期结果：

{"status":1,"content":[{"ucode":"123","name":"abc","lname":"xyz"},{"ucode":"431","name":"cdb","lname":"zsa"}]}

请指导我哪里出错了，没有得到预期的结果。

Answer 1

为什么需要循环，如果您可以直接将数据推入结果的内容索引中。

$result         = [];
$result["status"] = 1;
$data           = [
    ["ucode" => "123", "name" => "abc", "lname" => "xyz"],
    ["ucode" => "431", "name" => "cdb", "lname" => "zsa"],
];
$result['content'] = $data;
echo $res = json_encode($result);

简短形式

$result = ['status' => 1, 'content' => $data];
echo json_encode($result);

工作demo。

输出

{"status":1,"content":[{"ucode":"123","name":"abc","lname":"xyz"}, 
 {"ucode":"431","name":"cdb","lname":"zsa"}]}

Answer 2

您重用变量$data会导致问题。同样，当您追加到$result['content']数组时，也需要使用[]。

<?php
    $result = array(
        'content' => array(),
        'status' => 1
    );
    $data= array(
        array("ucode" => "123","name" => "abc","lname" => "xyz"),
        array("ucode" => "431","name" => "cdb","lname" => "zsa")
    );
    foreach($data as $res){ 
        $tmp = array(
            'ucode' => $res['ucode'],
            'name' => $res['name'],
            'lname' => $res['lname']
        );
        $result['content'][] = $tmp;
    }
    echo $res = json_encode($result);
?>

Answer 3

我还有另一种解决方法，就是和你们一起

因为当我使用json_encode（）传入api时，我想重命名变量名称。

  <?php
            $result=array();
            $result['status']=1;
            $data=array(
                      array("ucode" => "123","name" => "abc","lname" => "xyz"),
                      array("ucode" => "431","name" => "cdb","lname" => "zsa"),
                    );
            $ar=array();
            foreach($data as $res){
                $data=array();
                 $data['u_code']=$res['ucode'];
                 $data['u_name']= $res['name'];
                 $data['u_lname']= $res['lname'];
                 $ar[]=$data;
              }
            $result['content']=$ar;
            echo $res=json_encode($result);

      ?>

使用foreach循环将数组转换为json

3 个答案: