Question

我是Postgresql和Sqlalchemy的新手。我有下面的文件layout.py。在此，我在“ col”模式下创建了两个表名“ layout”和“ layout default”。

import json, decimal
from sqlalchemy.dialects.postgresql import UUID
from sqlalchemy import create_engine
from sqlalchemy import Column, String, Integer, TIMESTAMP, Sequence, text, types
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker
import datetime, uuid


db_string = "postgres://postgres:PWDd@10.**.**.***:1111/d_demo"

Base = declarative_base()
db = create_engine(db_string)

class Layout(Base):
    __tablename__ = "col.layout"
    layout_id = Column(UUID(as_uuid=True), nullable=False, primary_key=True)
    name = Column(String(1000), nullable=False)
    layout = Column(String(10000), nullable=False)
    grid_id = Column(Integer, nullable=False)
    user_id = Column(Integer, nullable=False)
    issystemlayout = Column(Integer, default=0, nullable=False)
    ispublic = Column(Integer, default=0, nullable=False)
    isactive = Column(Integer, default=0, nullable=False)
    createdby = Column(Integer, default=1, nullable=False)
    createdat = Column(TIMESTAMP, default=(datetime.datetime.now()), nullable=False)
    modifiedat = Column(TIMESTAMP, default=(datetime.datetime.now()), nullable=False)
    modifiedby = Column(Integer, default=1, nullable=False)

插入数据：

INSERT INTO col.layout(layout_id,name,layout,grid_id,user_id,ispublic,issystemlayout,isactive,createdby,createdat, modifiedat,modifiedby) VALUES('ba0233d7-d917-4303-b4bf-c2544a617d33','Layout1','{"Name":"Manish","Place":"Pune"}',1,12345,'1','0','1','201819','2015/05/20','2015/05/16',123);

获取数据：

Session = sessionmaker(bind=db)  
session = Session()
Base.metadata.create_all(db)
session.query("SET search_path TO col;") 

result = []
selected_columns = Layout.__table__.columns
print("Selected columns {}".format(selected_columns))
record = session.query(Layout).with_entities(*selected_columns).all()
for row in record:
    print(row)
    result.append(row)

print(json.dumps(result))

session.close()

但是它没有显示“ col”模式下的数据。请提出建议，我该怎么办？

Answer 1

https://docs.sqlalchemy.org/en/13/orm/extensions/declarative/table_config.html#table-configuration

Postgres数据库的架构可以通过 table_args 属性作为元组或dict传递。

因此，对于您的问题，您的类定义应具有以下额外属性：

class Layout(Base):
    __tablename__ = "layout"
    __table_args__ = {"schema": "col"}
    layout_id = Column(UUID(as_uuid=True), nullable=False, primary_key=True)
    name = Column(String(1000), nullable=False)
    layout = Column(String(10000), nullable=False)
    grid_id = Column(Integer, nullable=False)
    user_id = Column(Integer, nullable=False)
    issystemlayout = Column(Integer, default=0, nullable=False)
    ispublic = Column(Integer, default=0, nullable=False)
    isactive = Column(Integer, default=0, nullable=False)
    createdby = Column(Integer, default=1, nullable=False)
    createdat = Column(TIMESTAMP, default=(datetime.datetime.now()), nullable=False)
    modifiedat = Column(TIMESTAMP, default=(datetime.datetime.now()), nullable=False)
    modifiedby = Column(Integer, default=1, nullable=False)

如何通过指定架构从Postgresql数据库中获取行？

1 个答案: