Question

json values in toast type在我的项目中从服务器端获取数据，因为我正在发送带有嵌套数组的数组作为响应。在此图中，您可以看到带有数组的“ Secondary_number”具有一些值。我需要打印这些值。我附上了我的java代码。当我尝试运行此屏幕时，我的屏幕变黑。

JSONObject obj = new JSONObject(response);
JSONArray jsonArray = obj.getJSONArray("response");
service = new String[jsonArray.length()];
//Iterate the jsonArray and print the info of JSONObjects
for (int i = 0; i < jsonArray.length(); i++) {
     JSONObject jsonObject = jsonArray.getJSONObject(i)
//getting second array
      JSONArray jArray = jsonObject.getJSONArray("secondary_number");

    //Iterate the jsonArray and print the info of JSONObjects
      for (int j = 0; j < jArray.length(); j++) { 
              do some computation
}
  service[i] = jsonObject.getString("service_id").toString(); //getting values in response 
  tv1 = jsonObject.getString("service_id");
  tv2 = jsonObject.getString("user_id").toString();
  tv3 = jsonObject.getString("username").toString();
  tv4 = jsonObject.getString("company_name").toString();
  tv5 = jsonObject.getString("assigned_time").toString();

请为此提供帮助

Answer 1

前两行都可以

JSONObject obj = new JSONObject(response);
JSONArray services = obj.getJSONArray("response");

但是在那之后，不是。我不知道您想做什么，可能是出于调试目的，所以我不会做任何事情。另外，我将得到字符串以使其清楚。

for(int i = 0; i < services.length(); i++){
    JSONObject service = services.getJSONObject(i);

    tv1 = service.getString("service_id");
    tv2 = service.getString("assigned_time");
    tv3 = service.getString("company_name");
    tv4 = service.getString("user_id");
    tv5 = service.getString("username");
    //for some reason, secondary_number value is escaped which mean 
    //it is a string that you will have to parse
    String secondary_number = service.getString("secondary_number");
    JSONArray secondary_number_json = new JSONArray(secondary_number);

    for(int j = 0; j < secondary_number_json.length(); j++){
        JSONObject secondary = secondary_number_json.getJSONObject(j);
        String name = secondary .getString("name");
        String alternative_no = secondary .getString("alternative_no");
        String designation = secondary .getString("designation");
        // do things with those strings
    }
}

为了更好地利用数据，您应该查看Gson库，以便使用pojo类更轻松地解析json

请，请帮助我..我正在做一个项目，并且正在从Web服务获取JSON格式的数据

1 个答案: