我想使用Single作为返回类型,或者如果为null,则可能为空。
首先,我调用一个方法来获取布尔值:
Single<Boolean> isRemembered()
然后,如果此方法返回true,则调用此方法:
Single<String> getRemembered()
如果isRemembered()返回true,则getRemembered()永远不会为空值。
这是我在直播中的尝试:
public Maybe<String> getRememberIfExists(){
return sharedPreferencesRepositoryType.isRemembered()
.flatMapMaybe(aBoolean -> {
if(aBoolean){
return sharedPreferencesRepositoryType.getRemembered()
.flatMapMaybe(Maybe::just);
}else{
return Maybe.empty();
}
});
}
当isRemembered()返回true和false时,我都写了一个测试:
@Test
public void getRememberIfExists() {
when(repository.getRemembered()).thenReturn(Single.just(REMEMBERED));
when(repository.isRemembered()).thenReturn(Single.just(true));
TestObserver<String> observer = interactor.getRememberIfExists()
.test();
verify(repository).isRemembered();
verify(repository).getRemembered();
observer.assertNoErrors()
.assertComplete()
.assertValueCount(1);
assertEquals(REMEMBERED, observer.values().get(0));
}
@Test
public void getRememberIfExistsError(){
when(repository.isRemembered()).thenReturn(Single.just(false));
TestObserver<String> testObserver = interactor.getRememberIfExists()
.test();
verify(repository).isRemembered();
testObserver.assertComplete();
testObserver.assertEmpty();
}
第一次测试成功。第二个失败:
java.lang.AssertionError: Completed! (latch = 0, values = 0, errors = 0, completions = 1)
在:
testObserver.assertEmpty()
关于如何正确编写上述getRememberIfExists()方法的任何建议?
答案 0 :(得分:2)
根据reference doc, assertEmpty
返回一个(单个)Maybe实例,该实例立即调用onComplete。
因此,请使用“ assertNoValues”代替“ assertEmpty”:
@Test
public void getRememberIfExistsError(){
when(repository.isRemembered()).thenReturn(Single.just(false));
TestObserver<String> testObserver = interactor.getRememberIfExists()
.test();
verify(repository).isRemembered();
testObserver.assertComplete();
testObserver.assertNoValues()
}