即使if语句仍为False，该语句仍会运行

Question

因此，如果if语句为False，它仍然会运行。

我正在尝试查看是否有人拉着脸卡，然后打印出一些东西。但是，即使我知道if语句为False的事实，它仍然可以运行。

pulls card

def deck():
    global rank
    ranks = [ "9", "8", "7",
    "5", "4", "3", "2", "Ace"]

通知等级没有人脸卡

    suits = ["Clubs", "Spades", "Diamonds", "Hearts"]

    for i in range(1):
        rank = random.choice(ranks)

        suit = random.choice(suits)
        # dont allow same card to be played
        card = ("{} of {}").format(rank, suit)
    return card

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prints card
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def print_card():
    global cardV, card
    if hit_or_stand() == True:
        card = deck()
        print(str(card))

        cardV = []
        cardV.append(rank)
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notice that cardV should not be a face card
``````````````
def player_count():

    if cardV == ["King"] or ["Queen"] or ["Jack"]:

        print("it works")

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and even if it prints 8 of Spades, it still prints "it works"
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