如何以列格式打印斐波那契数字

Question

我需要一些帮助，尝试以以下格式打印：

00: 0   
01: 1   
02: 1   
03: 2   
04: 3   
05: 5   
06: 8   
07: 13  
08: 21  
09: 34  
10: 55  

我的代码：

import math
import time

start_time = time.time()
golden_ratio = (1 + math.sqrt(5)) / 2

def  main():
    num = int(input("How many Fibonacci numbers should I print? "))

    for number in range(0,num+1):
        val = (golden_ratio**number - (1 - golden_ratio)**number) / math.sqrt(5)
        print(format(round((val)),'3d'))

main()

Answer 1

import math
import time

start_time = time.time()
golden_ratio = (1 + math.sqrt(5)) / 2

def  main():
    num = int(input("How many Fibonacci numbers should I print? "))

    for number in range(0,num+1):
        val = (golden_ratio**number - (1 - golden_ratio)**number) / math.sqrt(5)
        print('{}: {:.0f}'.format(number, val))

main()

Answer 2

import math
import time

start_time = time.time()
golden_ratio = (1 + math.sqrt(5)) / 2

def  main():
    num = int(input("How many Fibonacci numbers should I print? "))

    for number in range(0,num+1):
        val = (golden_ratio**number - (1 - golden_ratio)**number) / math.sqrt(5)
        print(format(number, '02d'), ': ', format(round((val)),'3d'))

main()

Answer 3

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            f"{os.getcwd()}/foods.txt",
            encoding="cp1252",
            blocksize="10MB",
            linedelimiter="\n\n",
        )
        .map_partitions(lambda x: "".join(x).split("\n\n"))

def main(): stnum = input("How many Fibonacci numbers should I print? ") dig = len(stnum) num = int(stnum) for number in range(0,num+1): val = (golden_ratio**number - (1 - golden_ratio)**number) / math.sqrt(5) #print(format(round((val)),'3d')) print(f"{number:0{dig}d}: {val:.0f}") 是斐波那契数字数量的位数：如果您要求输入100斐波那契数字，则dig为3。我使用formatted string literals（自python 3.6起可用）来格式化输出。
dig打印整数{number:0{dig}d}，其中number前导0。
dig在点后打印没有数字的浮点数。

如果您使用的是python的旧版本，并且格式化的字符串文字不可用，请使用以下命令替换print语句：

{val:.0f}