Question

我有2张桌子：

人物表：

id  |  name |  date
1   |  Mika |  2013
2   |  Rose |  2015

工作表：

id  |  user_id  |  work_name  |  registers
1   |     1     |    rugby    |     10
2   |     1     |    golf     |      3

我使用此查询来联接表：

SELECT * FROM work INNER JOIN people ON work.user_id = people.id WHERE work_name= :work_name

这可以工作，但是当我尝试打印阵营ID时，却得到了重复的列ID和php，这显示了最后一个列ID。我尝试使用此方法，但不起作用：

SELECT *, id AS 'work_id' 
FROM work 
INNER JOIN people ON work.user_id = people.id 
WHERE work_name= :work_name

Answer 1

这是因为您正在*中使用SELECT，这意味着将从两个表中带走所有字段，而您可以使用

SELECT   work.id  as work_id, 
         work.name as work_name, 
         work.date as work_date,
         people.id as people_id, 
         people.name as people_name, 
         people.date as people_date

Answer 2

尝试手动列出您需要显示的所有列，例如

SELECT w.user_id, w.work_name, w.registers, p.name, p.date FROM work as w INNER JOIN people as p ON work.user_id = people.id WHERE work_name= :work_name

使用内部联接在SELECT中设置别名

2 个答案: