Question

我的代码中唯一有问题的部分是将具有最多2000行数据的字符串与具有1条数据（用户输入）的字符串进行比较的部分。我添加了else语句以表明if语句永远不会为真。我的老师无法弄清楚为什么它将评估为假。谁能告诉我为什么该陈述总是错误的，以及如何解决？

//
//  main.cpp
//  Assignment 5
//
//

    #include <iostream>
    #include <string>
    #include <stdlib.h>
    #include <iomanip>
    #include <fstream>//for fin and fout
    #include <string>
    using namespace std;

int main()
{
    //declare input and output file stream
    ifstream fin;//in_s, inStream, input...
    string name[2000], inName;//name is the string for the file, inName is the users name
    string number[2000];
    char again;
    cout << "Welcome to the automated phone directory! " << endl << endl;


    //Open the file streams and associate with the actual files
    fin.open("/Users/ryoncook/Documents/School/Comp Sci/Assignments/Assignment 5/Asn Five_M/phoneNames.txt");
    if (fin.fail())
    {
        cout << "Input file opening failed" << endl;
        exit(1);//indicates 1 error occured
    }

    for(int i=0; i < 2000; i++)//loops until desired maximum size
    {
        getline(fin,name[i]);//stores the values of the file in the string array
    }
    fin.close();

    //open number file
    fin.open("/Users/ryoncook/Documents/School/Comp Sci/Assignments/Assignment 5/Asn Five_M/phoneNums.txt");
    if (fin.fail())
    {
        cout << "Input file opening failed" << endl;
        exit(1);//indicates 1 error occured
    }

    for(int i=0; i < 2000; i++)//loops until desired maximum size
    {
        getline(fin,number[i]);//stores the values of the file in the string array
    }
    //Close all open files
    fin.close();
    do{
    cout << "Enter the name of the person you wish to look up: " << endl;
    inName.clear();
    getline(cin,inName);//reads the name desired as a string
    for (int i=0; i < 2000; i++)
    {
        if (name[i] == inName)//compares input name with file name
        {
            cout << name[i] << "'s phone number is " << number[i] << endl;//prints result
        }
        else
        {
            cout << name[i] << inName;//i ran an else statement to confirm.  The out if statement is never evaluated to be true
        }
    }

    cout << "Would you like to find another phone number? (Y or N) " << endl;
    cin >> again;
    }while (again=='y' || again=='Y');
    return 0;

}
//array for phone numbers and array for names that are both strings
//compare the 2 arrays and if they are equal, print

for循环应找到用户输入的名称，如果在文件中，则应选择正确的名称和电话号码。实际上发生的是，即使输入的名称在文件中，该语句也永远不会为真。

我知道if语句是问题所在，因为我打印了一些具有不同数字（例如number [12]，name [6]等）的名称和数字字符串，并且它们都打印了正确的名称/数字

将具有2000个值的字符串与具有1个值的字符串进行比较

0 个答案: