嗨, 我遵循了有关多模型搜索的教程,并且该方法有效。现在我想对输出进行分页。但是如何将分页页面(下一个/上一个)数据加载到模板中?到目前为止,如果我按下 next ,我会得到一个错误。
views.py
from django.views.generic import TemplateView, ListView
from django.views.generic import View
from django.shortcuts import render
from django.db.models import Q
from django.core.paginator import Paginator
from itertools import chain
# --- Import Models
from datainput.models import Animal
from datainput.models import Farmer
<....>
class SearchView(ListView):
template_name = 'farmapi/searchview.html'
paginate_by = 2
count = 0
def get_context_data(self, *args, **kwargs):
context = super().get_context_data(*args, **kwargs)
context['count'] = self.count or 0
context['query'] = self.request.GET.get('q')
return context
def get_queryset(self):
request = self.request
query = request.GET.get('q', None)
if query is not None:
farmer_results = Farmer.objects.search(query)
animal_results = Animal.objects.search(query)
# combine querysets
queryset_chain = chain(
farmer_results,
animal_results
)
qs = sorted(queryset_chain,
key=lambda instance: instance.pk,
reverse=True)
self.count = len(qs) # since qs is actually a list
return qs
return Farmer.objects.none() # just an empty queryset as default
template.html
{% extends 'base.html' %}
{% load class_name %}
{% load static %}
{% block custom_css %}
<link rel="stylesheet" type="text/css" href="{% static 'css/home_styles.css' %}">
{% endblock %}
{% block content %}
<div style="height: 10px;">
</div>
<div class="container-fluid">
<div class='row'>
<div class="col-4 offset-md-8">
<form method='GET' class='' action='.'>
<div class="input-group form-group-no-border mx-auto" style="margin-bottom: 0px; font-size: 32px;">
<span class="input-group-addon cfe-nav" style='color:#000'>
<i class="fa fa-search" aria-hidden="true"></i>
</span>
<input type="text" name="q" data-toggle="popover" data-placement="bottom" data-content="Press enter to search" class="form-control cfe-nav mt-0 py-3" placeholder="Search..." value="" style="" data-original-title="" title="" autofocus="autofocus">
</div>
</form>
</div>
</div>
</div>
<div style="height: 10px;">
</div>
<div class="container-fluid">
<div class="row">
<div class="col-6 offset-md-4">
{% for object in object_list %}
{% with object|class_name as klass %}
{% if klass == 'Farmer' %}
<div class='row'>
Farmer: <a href='{{ object.get_absolute_url }}'> {{ object.first_name }} {{ object.last_name }}</a>
</div>
{% elif klass == 'Animal' %}
<div class='row'>
Animal: <a href='{{ object.get_absolute_url }}'> {{ object.name }} {{ object.species }}</a>
</div>
{% else %}
<div class='row'>
<a href='{{ object.get_absolute_url }}'>{{ object }} | {{ object|class_name }}</a>
</div>
{% endif %}
{% endwith %}
{% empty %}
{% endfor %}
<div style="height: 10px;">
</div>
<div class='row'>
<results>{{ count }} results for <b>{{ query }}</b></results>
</div>
</div>
</div>
</div>
<div class="container-fluid">
<!-- Pagniator Data -->
<div class="paginator">
<span class="step-links">
<span class="current">
Page {{ page_obj.number }} of {{ page_obj.paginator.num_pages }}.
</span>
{% if page_obj.has_previous %}
<a href="?page=1">« first</a>
<a href="?page={{ page_obj.previous_page_number }}">previous</a>
{% endif %}
{% if page_obj.has_next %}
<a href="?page={{ page_obj.next_page_number }}">next</a>
<a href="?page={{ page_obj.paginator.num_pages }}">last »</a>
{% endif %}
</span>
</div>
</div>
{% endblock %}
如果我的模板向我显示了例如“ xyz的4个结果” 和“第1页,共2页” ,并且我按下了下一个或最后页,然后我收到此错误消息:
找不到页面(404)请求方法:GET请求URL: the wiki提出者: farmapi.views.SearchView
无效页面(2):该页面不包含任何结果
据我了解,我必须显式分页查询集的返回值,以便分页器将其放入?还是我错过了请求分页器的请求?
答案 0 :(得分:0)
我还使用了分页器,用户可以定义每页的项目数。我添加了以下方法:
def get_paginate_by(self, queryset):
limit = int(self.request.POST.get('limit', 25))
return limit
在模板中,它看起来像:
{% if is_paginated %}
{{ page_obj|render_paginator }}
{% endif %}
其中render_paginator是模板标记。 在您的模板中调用一个网址,例如:your_url?page = 2