Question

我试图以内联方式显示链接列表元素，而不是将其放在换行中。

我本来以为是因为我有/n和endl在新行中显示，所以我删除了它们，但它们仍在新行中显示。

// display function
    void display()
    {
        Node*current = head;

        while (current != NULL)
        {
            cout << "Queue";
            cout << current->value << " ";
            cout << endl;
            current = current->next;
        }


    }

// adding to queue function
void enqueue(int num) {

        Node *node = new Node(num);
        cout << "Pushing: " << num << endl;
        if (tail != NULL)
        {
            tail->next = node;
        }
        tail = node;
        if (head == NULL)
        {
            head = node;
        }
        display();

    }

每次我将某项推送到队列时，它都会显示正在推送的值以及队列中当前存储的值。每次我推东西时都打印什么

// Results
Pushing 1
Queue: 1
Pushing 2 
Queue: 2
Pushing 3
Queue: 3

// What I want to display
Pushing 1
Queue: 1
Pushing 2
Queue: 1 2
Pushing 3
Queue: 1 2 3

Answer 1

将cout<<endl放在循环之外：

void display()
{
    Node*current = head;

    while (current != NULL)
    {
        cout << "Queue";
        cout << current->value << " ";
        current = current->next;
    }

    cout << endl;

}

内联显示链接列表

1 个答案: