如何使用数组中的一个键添加多个键?
def apidurusanalizi_func(self):
isyerleri = data.iloc[:,0].values
hatalar = np.delete(data.columns, 0)
cluster1 = []
for i,row in enumerate(bc):
for j, y in enumerate(row):
if y:
isyeri = isyerleri[i]
hata = hatalar[j]
record = {"isyeri":str(isyeri), hata.lower().replace(" ", ""):hata}
if index == 0:
cluster1.append(record)/*add record*/
return HttpResponse(json.dumps({'cluster1': cluster1}, indent=2), content_type="application/json")
输出如下:
{
"cluster1": [
{
"isyeri": "15400002",/*the same key*/
"olcmeodasi": "OLCME ODASI"
},
{
"isyeri": "15400002",/*the same key*/
"tipdegayari": "TIP DEG AYARI"
}
}
我要采用的JSON格式如下:
{
"cluster1": [
{
"isyeri": "15400002", /* the same value for two values */
"olcmeodasi": "OLCME ODASI"
"tipdegayari": "TIP DEG AYARI"
}
}
答案 0 :(得分:0)
您要创建的集群不是作为字典,而是作为列表:cluster1 = []
,然后在其后附加字典:cluster1.append(record)
。您应该将cluster1
定义为dict并设置记录值。
您的代码不是独立的,不能进行完整的测试,但这应该可以工作:
def apidurusanalizi_func(data):
isyerleri = data.iloc[:,0].values
hatalar = np.delete(data.columns, 0)
cluster1 = {}
for i,row in enumerate(bc):
for j, y in enumerate(row):
if y:
isyeri = isyerleri[i]
hata = hatalar[j]
if index == 0:
cluster1["isyeri"] = str(isyeri)
cluster1[hata.lower().replace(" ", "")] = hata
return HttpResponse(
json.dumps({'cluster1': cluster1}, indent=2),
content_type="application/json"
)