Question

我正在尝试将两个json有效负载添加到一个中，但出现错误。我正在使用散点收集，在此我将获得多个有效负载并将有效负载组合到转换消息中。错误是：执行时发生异常：有效载荷[0]映射（bookListing）->使用（id = bookListing.bookId）{ “地图”运算符的类型不匹配找到：string，：function 必需的：array，：function。

代码：

      <http:listener-config name="HTTP_Listener_Configuration" host="0.0.0.0" port="8081" doc:name="HTTP Listener Configuration"/>
<file:connector name="file-connector-config" autoDelete="false" streaming="true" validateConnections="true" doc:name="File" />
<flow name="muleRequester">
    <http:listener config-ref="HTTP_Listener_Configuration" path="/requester" doc:name="HTTP"/>
    <scatter-gather doc:name="Scatter-Gather">
        <processor-chain>
            <mulerequester:request resource="file://src/main/resources/input1" returnClass="java.lang.String" doc:name="Retrieve File1"/>
            <logger message="#[payload]" level="INFO" doc:name="Logger"/>
        </processor-chain>
        <processor-chain>
            <mulerequester:request resource="file://src/main/resources/input2" returnClass="java.lang.String" doc:name="Retrieve File2"/>
            <logger message="#[payload]" level="INFO" doc:name="Logger"/>
        </processor-chain>
    </scatter-gather>
    <dw:transform-message doc:name="Transform Message">
        <dw:set-payload><![CDATA[%dw 1.0
         %output application/json
         ---
         payload[0]  map (bookListing) -> using (id = bookListing.bookId) {
bookId: id,
title:  bookListing.title,
price:  bookListing.price,
(payload[1] filter ($.*bookId contains id)  map (bookAuthor) -> {
    author:bookAuthor.author
        })
    }]]></dw:set-payload>
     </dw:transform-message>
     <file:outbound-endpoint responseTimeout="10000" doc:name="File" outputPattern="#[function:systime].json" path="src/main/resources/output"/>
    <logger message="#[payload]" level="INFO" doc:name="Logger"/>
</flow>

有效负载1- [ { “ bookId”：“ 101”， “ title”：“世界历史”， “价格”：“ 19.99” }， { “ bookId”：“ 202”， “ title”：“户外活动很棒”， “价格”：“ 15.99” } ]

有效载荷2- [ { “ bookId”：“ 101”， “ author”：“ john doe” }， { “ bookId”：“ 202”， “作者”：“珍妮·多伊” } ]

预期输出-

[ { “ bookId”：“ 101”， “ title”：“世界历史”， “年份”：“ 2017”， “ isbn”：“ 11111”， “ price”：“ 19.99”， “ author”：“ john doe” }， { “ bookId”：“ 202”， “ title”：“户外活动很棒”， “年份”：“ 2016”， “ isbn”：“ 22222”， “ price”：“ 15.99”， “ author”：“ jane doe” } ]

Answer 1

文件返回的值只是字符串，因此需要先将它们读入dataweave可以使用的值中。像这样使用读取功能：

read(payload[0], 'application/json')

和

read(payload[1], 'application/json')

这里是一个完整的例子。（我已经在分散收集中存入了示例json）：

    <scatter-gather doc:name="Scatter-Gather">
       <set-payload value="[ { &quot;bookId&quot;:&quot;101&quot;, &quot;title&quot;:&quot;world history&quot;, &quot;price&quot;:&quot;19.99&quot; }, { &quot;bookId&quot;:&quot;202&quot;, &quot;title&quot;:&quot;the great outdoors&quot;, &quot;price&quot;:&quot;15.99&quot; } ]" doc:name="payload1"/>
       <set-payload value="[ { &quot;bookId&quot;:&quot;101&quot;, &quot;author&quot;:&quot;john doe&quot; }, { &quot;bookId&quot;:&quot;202&quot;, &quot;author&quot;:&quot;jane doe&quot; } ]" doc:name="payload2"/>
    </scatter-gather>

    <dw:transform-message doc:name="Transform Message">
       <dw:set-payload><![CDATA[%dw 1.0
%output application/json
---
read(payload[0], 'application/json')  map (bookListing) -> using (id = bookListing.bookId) {
bookId: id,
title:  bookListing.title,
price:  bookListing.price,
(read(payload[1], 'application/json') filter ($.*bookId contains id)  map (bookAuthor) -> {
    author:bookAuthor.author
})
}]]></dw:set-payload>
   </dw:transform-message>

或者您可以先将整个内容读入Json

“在转换组件中将两个有效载荷合并为一个”

1 个答案: