我要重命名的文件夹中有许多CSV文件。有一个Excel工作表,其中包含要重命名为文件夹的文件的名称。
文件夹中的文件命名为
TestData_30April.csv
TestData_20April.csv
TestData_18April.csv等
而Excel工作表中的名称为
0.25-TestData_30April
0.98-TestData_20April
0.33-TestData_20April等
我的目标是重命名
对于所有其他文件,从“ TestData_30April.csv”到“ 0.25-TestData_30April.csv”也是如此。
这是我编写的代码(无法正常工作)
import os
import xlrd
#Excel Sheet containing name of files to be renamed in that folder
path="C:\\Users\\Desktop\\Test_Data\\Test_Summary.xlsx"
#Folder Containg all orginal file names
dir = "C:\\Users\\Desktop\\Wear_Data"
wb = xlrd.open_workbook(path)
sheet = wb.sheet_by_index(0)
sheet.cell_value(0, 0)
#In excel sheet column X or col_values(23) contains the file name to be renamed
print(sheet.col_values(23))
list_of_filename_in_folder = [] # name of the files in the folder
list_of_filename_in_excel = [] #name of the files in excel
path_to_folder = '' # base path of folder
for name in list_of_filename_in_excel:
excel_file_name = os.path.join(path_to_folder, name,'.csv')
dir_file_name = os.path.join(path_to_folder,name.split('-')[1],'.csv' )
if os.path.exists(dir_file_name):
print('changing file name {} to {}'.format(name.split('-')[1],name))
os.rename(dir_file_name, excel_file_name)
else:
print('no file {} with name found in location'.format(name.split('-')[1]+'.csv')
答案 0 :(得分:1)
Edit2: 根据excel文件示例,尝试以下代码:
if not request.json or not 'fac_name' in request.json:
旧答案
编辑: 下例中文件“ myfile.csv”的内容为:
import os
with open('myfile.csv', encoding='utf-8') as f:
buff = f.read()
buff = buff.splitlines()[1:]
for data in buff:
data = data.split(',')
old_name, new_name = data[21] + '.csv', data[23] + '.csv'
if os.path.exists(old_name):
print('changing file name {} to {}'.format(old_name,new_name))
os.rename(old_name, new_name)
else:
print('no file {} with name found in location'.format(old_name))
如果您在读取文件时遇到问题,请首先确保它是csv格式的文件,并且可以在任何文本编辑器中打开它,如果仍然有问题,可以尝试使用encoding ='utf-8'打开它:
0.25-TestData_30April
0.98-TestData_20April
0.33-TestData_20April
您可以根据您的excel文件(csv文件)尝试以下简单代码
with open('myfile.csv', , encoding='utf-8') as f:
file_names = f.read().split()
已测试的输出:
import os
with open('myfile.csv') as f:
file_names = f.read().split()
for name in file_names:
new_name = name + '.csv'
old_name = name.split('-')[-1] + '.csv'
if os.path.exists(old_name):
print('changing file name {} to {}'.format(old_name,new_name))
os.rename(old_name, new_name)
else:
print('no file {} with name found in location'.format(old_name))