Question

我有一个如下查询，想通过将isMatchingNameEmail传递给第二种情况来整理它，

我的最终目标是通过以下逻辑找到匹配的referenceID：

返回数据库的referenceID 如果名字+电子邮件地址上有任何匹配项，如果不匹配，则尝试找到与名字和手机号上匹配的内容，如果不是，则返回

只想看看是否有更好的方法可以做到。谢谢大家！

    select r.*,
    L.U3L_ReferenceID ReferenceID,
    case when L.U3L_ReferenceID is null then
        (select L.U3L_ReferenceID from [u3_data].[data].[ListData_e0a27] [L]
        where r.given_name = L.firstname and r.email = L.emailaddress)
        end isMatchingNameEmail,
    -- when record is not found and isMatchingNameEmail is null
    case when L.U3L_ReferenceID is null
        and (select top 1 L.U3L_ReferenceID from [u3_data].[data].[ListData_e0a27] [L]
        where r.given_name = L.firstname and r.email = L.emailaddress) is null
        then
        (select L.U3L_ReferenceID from [u3_data].[data].[ListData_e0a27] [L]
        where 
        r.given_name = L.firstname and
            (replace(
            replace( 
            replace(
            replace(r.mobilephone
                    ,' ','')
                    ,'(','')
                    ,')','')
                    ,'+','') = L.mobilenumber or
            replace(
            replace( 
            replace(
            replace(r.mobilephone
                    ,' ','')
                    ,'(','')
                    ,')','')
                    ,'+','') = stuff(L.mobilenumber,1,2,'0') or
            replace(
            replace( 
            replace(
            replace(r.mobilephone
                    ,' ','')
                    ,'(','')
                    ,')','')
                    ,'+','') = L.mobilenumber))
        end isMatchingNameMobile
    from @Records r
    left Join [u3_data].[data].[ListData_e0a27] [L] with(nolock) on
    [r].Id = [L].userid

Answer 1

使用CTE

; with 
cte1 as
(
    select col1, col2, <query expression> as col3 from yourtable
),
cte2 as
(
    select col1, col2, col3, col3 * 4 as col4 from cte1
)
select col1, col2, col3, col4 
from   cte2

使用派生表

select col1, col2, col3, col4
from
(
     select col1, col2, col3, col3 * 4 as col4
     from
     (
         select col1, col3, <query expression> as col3 from yourtable
     ) as d
) as d

使用应用运算符

select t.col1, t.col2, a3.col3, a4.col4
from   yourtable t
       cross apply
       (
            select <query expression> as col3
       ) a1
       cross apply
       (
            select col3 * 4 as col4
       ) a

将变量传递给另一种情况时传递条件

1 个答案: