我试图将程序从Python(2.7,32位)转换为Go(1.12.5,32位),但由于访问冲突而失败。该程序在32位dll(ehlapi32.dll)中调用一个函数。
以下Python代码片段似乎运行良好(我不确定它们是正确的!):
class ehlapi32:
hllDll = "C:\Program Files (x86)\IBM\Personal Communications\EHLAPI32.dll"
hllDll = ctypes.WinDLL(hllDll)
hllApiProto = ctypes.WINFUNCTYPE(ctypes.c_int,ctypes.c_void_p,ctypes.c_void_p,
ctypes.c_void_p,ctypes.c_void_p)
hllApiParams = (1, "p1", 0), (1, "p2", 0), (1, "p3",0), (1, "p4",0),
hllApi = hllApiProto (("HLLAPI", hllDll), hllApiParams)
pFunConnect = ctypes.c_int(1)
...
def connect(self):
shlSession = self.session + b'\0\0\0'
pText = ctypes.c_char_p (shlSession)
pLength = ctypes.c_int (len(shlSession))
pReturn = ctypes.c_int (13)
ehlapi32.hllApi (ctypes.byref (ehlapi32.pFunConnect), pText,
ctypes.byref (pLength), ctypes.byref (pReturn))
现在这就是我正在尝试的Go等效项。失败:
// ElFunc: EHLLAPI Functions
type ElFunc uint32
const (
eConnect ElFunc = 1 // Connect to a terminal
)
...
// Session: a 3270 session handle
type Session struct {
SessId string
SysId string
Entry string
Result []string
Headers int
Footers int
Rows int
Cols int
Scroll int
Proc *syscall.LazyProc
}
...
func (s Session) Connect() uint32 {
// Load EHLLAPI DLL
dll := syscall.NewLazyDLL(dllName)
s.Proc = dll.NewProc(dllProc)
// Connect to session
rc := s.ecall(eConnect, s.SessId, 1, 0)
if rc == 0 {
defer s.Disconnect()
}
...
// ecall: provides simplified EHLLAPI DLL calls
func (s Session) ecall(fun ElFunc, buffer string, count uint32, ps uint32) uint32 {
rc := ps
_, _, _ = s.Proc.Call(
uintptr(unsafe.Pointer(uintptr(uint32(fun)))),
uintptr(unsafe.Pointer(&buffer)),
uintptr(unsafe.Pointer(uintptr(count))),
uintptr(unsafe.Pointer(uintptr(rc))),
)
return rc
}
失败看起来像是s.Proc.Call
中ecall()
处的访问冲突。
我意识到syscall
已过时;我也尝试过golang.org/x/sys/windows
,但没有成功。我对使用哪个没有任何限制。
我要承认我在这里超出了我的深度。