Question

首先，我会道歉，我对jquery / javascript的了解不是很好，所以我的错误对于某些人来说可能非常明显，但我仍然在学习，所以要谦和！！

我有一个表格，该表格允许成员从数据库中删除他们发表的帖子。表单工作正常，使用php可以根据需要从数据库中删除数据。我想创建一个弹出窗口，让用户确认这就是他们想做的事情。我不想使用特定于沼泽标准浏览器的onclick方法，我想要一些可定制的东西。因此，我尝试使用bootbox，当前在确认对话框中弹出onclick，但是当您选择yes时，则什么也没有发生。我怀疑jquery的结果没有触发表单，但是从我阅读的那部分代码来看是好的？

我已经在php，jquery和html下面粘贴了

PHP：

<?php
$deletepost = 'none';
$deleteposterror = 'none';

if(isset($_POST['delete'])) {

    $del_topic_id = $_POST['topic_id_value'];

    // sql to delete a record
    $pass_fail = "DELETE FROM topics WHERE topic_id ='$del_topic_id';";

    $pass_fail .= "DELETE FROM posts WHERE topic_id_post ='$del_topic_id'";

    if (mysqli_multi_query($conn, $pass_fail)) {

    $deletepost = 'show';

    }else{

    $deleteposterror = 'show';
    echo "ERROR: Could not able to execute $pass_fail. "  . mysqli_error($conn);    

    }

}
?>

while循环中的HTML和PHP：

<?php


            $sql1 = "SELECT * FROM topics WHERE topic_by = '".$id."' ORDER BY topic_date DESC ";
            $result1 = mysqli_query($conn, $sql1);

            while($row = $result1->fetch_assoc()) {

            $topic_id = $row ['topic_id'];
            $topic_subject = $row ['topic_subject']; 
            ?>



            <div class='chat_post_titles' >
            <div class='row'>
            <div class='col-md-7 chat_post_text_align_left'>
            <a href="../Chat/post.php?topic_id=<?php echo $topic_id?>"><?php echo $topic_subject?>.</a>
            </div>
            <div class='col-md-2 chat_post_text_align_right'>
            <?php
            $my_date = $row['topic_date'];
            $date = DATE("G:i:s d/m/Y",strtotime($my_date));
            ?>
            <div class='hide_text'>Post Date: </div>
            <?php echo $date?>
            </div>
            <div class='col-md-2 chat_post_text_align_centre'>
            <div class='hide_text'>Delete Post: </div>

            <form method="post" class="delete_post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
            <input type="hidden" name="topic_id_value" id="topic_id_value" value="<?php echo $topic_id?>">
            <button type="submit" name="delete" id="delete" class="btn btn-danger buttonElement">Delete</button>
            </form>
            </div>
            </div>
            </div>
            <?php
            }
            ?>

页面底部的JQUERY：

</body>
<?php include("../PHP/js.php"); ?>
<script type="text/javascript" src="../Members/updatedetails.js"></script>
<script type="text/javascript" src="../Members/bootbox.min.js"></script>
<script>

$('form').on('click','button.buttonElement',function (e) {
    var form = $(this).closest('form'); // <-- add this

    e.preventDefault();

    bootbox.confirm({
        message: "Are you sure you want to delete your post?", 
        title: "Delete Post",
        buttons: {
            cancel: { 
                label: "No", 
                className: "btn btn-default"
            },
            confirm: { 
                label: "Yes", 
                className: "btn btn-default"
            }
         },
         callback: function(result) {
             if(result == true) {
                 form.submit();
             }
         }
    });
 });

</script>

</html>

Answer 1

最后弄清楚了为什么我的代码在我使用的php中无法正常工作 if（isset（$ _ POST ['delete']））但是使用javascript submit()函数时，该名称attr被删除。因此，我使用了if(isset($_POST['topic_id_value']))之类的隐藏输入的名称，它可以正常工作。

仍然要感谢那些给我建议的人

引导程序确认后表单未提交

1 个答案: