Question

如何在一个数组中分别对2个对象数组进行排序？需要Lodash的解决方案。谢谢。

按年份排序的数组示例：

var objects = [[{
      year: 2010,
      name: "john",
      value: 30
    },
    {
      year: 2009,
      name: "john",
      value: 40
    }
  ],
  [{
      year: 2018,
      name: "bob",
      value: 40
    },
    {
      year: 2015,
      name: "bob",
      value: 30
    }]]

按年份排序后所需的输出：

[[{
      year: 2009,
      name: "john",
      value: 40
    },
    {
      year: 2010,
      name: "john",
      value: 30
    }
  ],
  [{
      year: 2015,
      name: "bob",
      value: 30
    },
    {
      year: 2018,
      name: "bob",
      value: 40
    }]]

Answer 1

每个子集合上的

orderBy应该足够

var objects = [
[{
year: 2010,
name: "john", 
value: 30
},
{
year: 2009,
name: "john",
value: 40
}],
[{
year: 2018,
name: "bob", 
value: 40
},
{
year: 2015,
name: "bob",
value: 30
}]
]

console.log(objects.map(subObject => _.orderBy(subObject, "year")));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

Answer 2

您可以在数组数组上使用map()并在map函数中返回排序后的数组。

var arr = [[{year:2010,name:"john",value:30},{year:2009,name:"john",value:40}],[{year:2018,name:"bob",value:40},{year:2015,name:"bob",value:30}]];


const res = arr.map(x => x.slice().sort((a,b) => a.year - b.year));
console.log(res)

Answer 3

您需要映射数组并对其进行排序：

const objects = [
[{
year: 2010,
name: "john", 
value: 30
},
{
year: 2009,
name: "john",
value: 40
}],
[{
year: 2018,
name: "bob", 
value: 40
},
{
year: 2015,
name: "bob",
value: 30
}]
] 

const sorted = objects.map(r=>r.sort((a,b)=>a.year - b.year));

console.log(sorted)

Answer 4

您可以使用_.partialRight()和_.map()到_.sortBy()子数组生成函数：

const { partialRight: pr, map, sortBy } = _;

const sortSubArrays = pr(map, arr => sortBy(arr, 'year'));

const objects = [[{year:2010,name:"john",value:30},{year:2009,name:"john",value:40}],[{year:2018,name:"bob",value:40},{year:2015,name:"bob",value:30}]];

const output = sortSubArrays(objects);

console.log(output);

.as-console-wrapper { max-height: 100% !important; top: auto; }

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.js"></script>

或使用lodash / fp并删除partialRight：

const { map, sortBy } = _;

const sortSubArrays = map(sortBy('year'));

const objects = [[{year:2010,name:"john",value:30},{year:2009,name:"john",value:40}],[{year:2018,name:"bob",value:40},{year:2015,name:"bob",value:30}]];

const output = sortSubArrays(objects);

console.log(output);

.as-console-wrapper { max-height: 100% !important; top: auto; }

<script src='https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js)'></script>

如何对数组中的不同对象数组进行排序

4 个答案: