Question

所以我有一个带有数据集的矩阵，我想要一个将矩阵中的所有值与数组进行比较的函数，以检查矩阵中的值是否存在于数组中，如果不存在则返回值的索引。

我尝试在

中设置一个dobbelt for循环

#the array with the values the matrixs values is compared 
Grades=np.array([-3,0,2,4,7,10,12])

#the dobbelt for loop
for u in range(0,len(data)):
        for j in range(0,len(data.T)):
            if not data[u,j] in Grades:
                # Error message is printed if a values isn't a found in the array.
                print("Error in {}, {}".format(u,j))

所有值我都出错了... 错误1,2，错误1,3，错误1,4，错误1,5 ...错误10,4，错误10,5，错误10,6，错误10,7 < / p>

Answer 1

由于您没有提供有问题的数据，所以我假设data为3*3 matrix，但是此代码适用于每个矩阵。

Grades=np.array([-3,0,2,4,7,10,12])
data = np.array([[1,2,3], [4,5,6], [7,8,9]])

#the dobbelt for loop
for u in range(data.shape[0]):
        for j in range(data.shape[1]):
            if data[u,j] not in Grades:
                # Error message is printed if a values isn't a found in the array.
                print("Error in {} for {} - {}".format(data[u,j], u,j))

输出：

Error in 1 for 0 - 0    # 1 is not present in given array and it's index is (0, 0)
Error in 3 for 0 - 2
Error in 5 for 1 - 1
Error in 6 for 1 - 2
Error in 8 for 2 - 1
Error in 9 for 2 - 2

我希望这可以解决您的查询。

检查矩阵中的值是否与数组中的值匹配，否则返回矩阵索引

1 个答案: