我需要我的登录用户,并且即使刷新后也要保持他的身份,我将其值放到了本地存储中。当我使用JSON.stringify()时,它将正确的值放置在本地存储中,但是在键名前面加上_,我不知道为什么(我将自己的私有属性_id命名为egid,但是我写了getters,我认为应该再次正常命名吗?)。因为它不起作用,所以我编写了自己的toJSON方法:
toJSON(): any {
return {
id: this._id,
firstName: this._firstName,
lastName: this._lastName,
email: this._email,
phoneNumber: this._phone,
country: this._country,
comments: this._comments.map(c => c.toJSON)
};
但是当我称它为“对象对象”时,它将[对象对象]放置到本地存储中,我不知道为什么会这么做。
我基本上需要使JSON.stringify将我的属性放置在localStorage中,或者我需要修复toJson。
import { Comment } from '../image/comment.model';
export class User {
constructor(
private _id: number,
private _firstName: string,
private _lastName: string,
private _email: string,
private _phone: string,
private _country: string,
private _comments: Comment[]
) {}
get id(): number {
return this._id;
}
get firstName(): string {
return this._firstName;
}
get lastName(): string {
return this._lastName;
}
get email(): string {
return this._email;
}
get phone(): string {
return this._phone;
}
get country(): string {
return this._country;
}
get comments(): Comment[] {
return this._comments;
}
static fromJSON(json: any): User {
return new User(
json.id,
json.firstName,
json.lastName,
json.email,
json.phoneNumber,
json.country,
json.comments
);
}
toJSON(): any {
return {
id: this._id,
firstName: this._firstName,
lastName: this._lastName,
email: this._email,
phoneNumber: this._phone,
country: this._country,
comments: this._comments.map(c => c.toJSON)
};
}
}
this.getUser(email).subscribe(usr => { //this gets my user via its email from the backend
localStorage.setItem('visitor', usr.toJSON());
this._loggedInUser$.next(usr);
});
this._loggedInUser$ = new BehaviorSubject<User>(
localStorage.getItem('visitor')
? User.fromJSON(localStorage.getItem('visitor'))
: null
);
get loggedInUser$(): BehaviorSubject<User> {
return this._loggedInUser$;
}
export class Comment {
private _id: number;
constructor(
private _author: string,
private _content: string,
private _date: Date,
private _imageId: number,
private _visitorId: number
) {}
get id(): number {
return this._id;
}
set id(value: number) {
this._id = value;
}
get author(): string {
return this._author;
}
get content() {
return this._content;
}
get date(): Date {
return this._date;
}
get imageId(): number {
return this._imageId;
}
get visitorId(): number {
return this._visitorId;
}
static fromJSON(json: any): Comment {
let comment = new Comment(
json.author,
json.content,
json.date,
json.myImageId,
json.visitorId
);
comment.id = json.id;
return comment;
}
toJSON(): any {
return {
id: this._id,
author: this._author,
content: this._content,
date: this._date,
myImageId: this._imageId,
visitorId: this._visitorId
};
}
}
如果需要更多代码,请告诉我!
答案 0 :(得分:0)
这可能是因为您给变量赋予了与JSON对象属性名称相同的名称。如果要删除下划线,请尝试为变量提供一些不同的名称。