Question

写出下面运行良好的代码：

def teams = ['x', 'y', 'z']
def list = [ [id:1, team1: 'x', team2:'y' ], [id:2, team1: 'z', team2:'y' ]]
def function = { 
    teams.inject( [:]) { result, team ->  
            result[team] = list.findAll { 
                team in [it.team1, it.team2] 
            }.size()
            result 
    }
}
println function()

结果如下：

[x:1, y:2, z:1]

现在，尝试将条件作为闭包传递给function，如下所示：

def function = { closure -> 
    teams.inject( [:]) { result, team ->
        result[team] = list.findAll(closure).size()
        result
    }
}

def t = { team in [it.team1, it.team2] }

println function(t)

但是它说下面的错误。 team在上下文中可用。

捕获：groovy.lang.MissingPropertyException：无此类属性：类团队：testclosure groovy.lang.MissingPropertyException：无此类属性：类团队：testclosure 在testclosure $ _run_closure3.doCall（testclosure.groovy：8）在testclosure $ _run_closure2 $ _closure6.doCall（testclosure.groovy：6）在testclosure $ _run_closure2.doCall（testclosure.groovy：6）在testclosure.run（testclosure.groovy：12）

有指针吗？

Answer 1

将所有必需参数传递给闭包的直接方法：

def teams = ['x', 'y', 'z']
def list = [ [id:1, team1: 'x', team2:'y' ], [id:2, team1: 'z', team2:'y' ]]

def function = { closure -> teams.inject( [:]) { result, team ->  
    result[team] = list.findAll{closure(team,it)}.size() 
    result 
} }

def t = {x1,x2-> x1 in [x2.team1, x2.team2]}

println function(t)

或者您可以使用rehydrate，但不能访问闭包参数：

def f = {_x,_y, closure->
    def x = _x
    def y = _y
    closure.rehydrate(this,this,this).call()
}


println f(111,222, {x+y})   //this works
println f(111,222, {_x+_y}) //this fails

Answer 2

表示我在groovy recipe上进行另一个名为curry的{{1}}的情况，如下所示：

closure

向groovy闭包传递参数

2 个答案: