当我单击图像时如何从图像中提交图像值

Question

所以我构建了搜寻器，可以从值中爬取链接中的所有数据，因此，我需要一种在单击图像时将图像的值输出到$_POST['']的方法，以及如何？

    require 'vendor/autoload.php';

    use Symfony\Component\DomCrawler\Crawler;

    $client = new \GuzzleHttp\Client();

    $furl = 'https://hentaifox.com';

    $res = $client->request('GET', $furl);

    $html = ''.$res->getBody();

    $crawler = new Crawler($html);

    $url_f = $crawler->filter('#content .galleries_overview .item')->each(function(crawler $node, $i) {
     //echo $node->html();
        $image = $node->filter('img')->attr('src');
        $src = $node->filter('a')->attr('href');
        $href = 'https://hentaifox.com/'. $src;

    ?>

    <form method="post" id="manga">
        <input type="image" name="<?php echo $src ?>" src="<?php echo $image ?>" width="120" height="168" value="<?php echo $href ?>">
    </form>

    <?php }); ?>