我正在尝试在ASP.NET MVC表下方编写一个“添加”按钮,以动态附加空白行,然后单击“提交”按钮以将每一行保存到数据库中。
SO上有several similar questions,但我没有一个可以应用于此。我一直在尝试应用this example,但“添加”按钮未附加新行。
型号:
public class TableForm
{
public int Id { get; set; }
public List<TableFormData> TableFormDatas { get; set; }
}
public class TableFormData
{
public int Id { get; set; }
public string ClientSampleID { get; set; }
public string AdditionalComments { get; set; }
public string AcidStables { get; set; }
剃刀视图:
@model NewTestSix.Models.TableForm
@{
ViewData["Title"] = "Create";
Layout = "~/Views/Shared/_Layout.cshtml";
}
@using (Html.BeginForm())
{
@Html.ValidationSummary(true)
<fieldset>
<legend>Sample submission</legend>
<table id="submissionTable" class="table table-bordered">
<thead>
<tr>
<td>Sample ID</td>
<td>Additional Comments</td>
<td>Acid-stable amino acids</td>
</tr>
</thead>
<tr id="tablerow0">
<td>
<div class="editor-field">
<input class="text-box single-line" name="ClientSampleID[0]" type="text" value="" required="required" />
</div>
</td>
<td>
<div class="editor-field">
<input class="text-box single-line" name="AdditionalComments[0]" type="text" value="" required="required" />
</div>
</td>
<td>
<div class="editor-field">
<input class="text-box single-line" name="AcidStables[0]" type="text" value="" />
</div>
</td>
<td>
<button type="button" class="btn btn-primary" onclick="removeTr(0);">Delete</button>
</td>
<td>
</td>
</tr>
</table>
<p>
<button id="add" type="submit" class="btn btn-primary">Add</button>
</p>
<hr />
<p>
<input type="submit" value="Create" class="btn btn-default" />
</p>
</fieldset>
}
@section Scripts {
<script src="~/bundles/jqueryval.js" type="text/javascript">
var counter = 1;
$(function () {
$('#add').click(function () {
$('<tr id="tablerow' + counter + '"><td>' +
'<input type="text" class="text-box single-line" name="ClientSampleID[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<input type="text" class="text-box single-line" name="AdditionalComments[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<input type="text" class="text-box single-line" name="AcidStables[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<button type="button" class="btn btn-primary" onclick="removeTr(' + counter + ');">Delete</button>' +
'</td>' +
'</tr>').appendTo('#submissionTable');
counter++;
return false;
});
});
function removeTr(index) {
if (counter > 1) {
$('#tablerow' + index).remove();
counter--;
}
return false;
}
</script>
在此阶段,我对与控制器的模型绑定并不太烦恼,我只想让此添加按钮起作用。控制器示例:
[HttpPost]
public ActionResult Index(string any = "")
{
IList<TableForm> _TableForm = new List<TableForm>();
//Loop through the forms
for (int i = 0; i <= Request.Form.Count; i++)
{
var ClientSampleID = Request.Form["ClientSampleID[" + i + "]"];
var additionalComments = Request.Form["AdditionalComments[" + i + "]"];
var acidStables = Request.Form["AcidStables[" + i + "]"];
if (!String.IsNullOrEmpty(ClientSampleID))
{
_TableForm.Add(new TableForm { ClientSampleID = ClientSampleID, AcidStables = acidStables, AdditionalComments = additionalComments });
}
}
return View();
}
感谢您的见解。
答案 0 :(得分:3)
更改您的
<button id="add" type="submit" class="btn btn-primary">Add</button>
进入
<button id="add" class="btn btn-primary">Add</button>
我不认为Add
按钮应该做submit
。
然后从您的src="~/bundles/jqueryval.js"
标记中删除script
部分。根据此answer,我们不应在此处保留src
属性。
赞
<script type="text/javascript">
var counter = 1;
//... the rest of your code is here...
</script>
如果您实际上有一个jqueryval.js
文件,请将其放在另一个<script>
标签中。
如果我没记错的话,这就是您所期望的结果。
var counter = 1;
$(function () {
$('#add').click(function () {
$('<tr id="tablerow' + counter + '"><td>' +
'<input type="text" class="text-box single-line" name="ClientSampleID[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<input type="text" class="text-box single-line" name="AdditionalComments[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<input type="text" class="text-box single-line" name="AcidStables[' + counter + ']" value="" required="required" />' +
'</td>' +
'<td>' +
'<button type="button" class="btn btn-primary" onclick="removeTr(' + counter + ');">Delete</button>' +
'</td>' +
'</tr>').appendTo('#submissionTable');
counter++;
return false;
});
});
function removeTr(index) {
if (counter > 1) {
$('#tablerow' + index).remove();
counter--;
}
return false;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<fieldset>
<legend>Sample submission</legend>
<table id="submissionTable" class="table table-bordered">
<thead>
<tr>
<td>Sample ID</td>
<td>Additional Comments</td>
<td>Acid-stable amino acids</td>
</tr>
</thead>
<tr id="tablerow0">
<td>
<div class="editor-field">
<input class="text-box single-line" name="ClientSampleID[0]" type="text" value="" required="required" />
</div>
</td>
<td>
<div class="editor-field">
<input class="text-box single-line" name="AdditionalComments[0]" type="text" value="" required="required" />
</div>
</td>
<td>
<div class="editor-field">
<input class="text-box single-line" name="AcidStables[0]" type="text" value="" />
</div>
</td>
<td>
<button type="button" class="btn btn-primary" onclick="removeTr(0);">Delete</button>
</td>
<td></td>
</tr>
</table>
<p>
<button id="add" type="button" class="btn btn-primary">Add</button>
</p>
<hr />
<p>
<input type="submit" value="Create" class="btn btn-default" />
</p>
</fieldset>
让我知道是否有帮助。
答案 1 :(得分:1)
您可以使用jQuery jqGrid
这是免费且开源的jquery插件。这是完全 已启用Ajax以显示表格数据并进行操作。另外, 我们可以应用不同的Jquery UI主题,请参见演示。
操作方法:这里没有任何内容,因为我们将使用json格式的Ajax获取产品详细信息。
public ActionResult GetProducts(string sidx, string sord, int page, int rows)
{
var products = Product.GetSampleProducts();
int pageIndex = Convert.ToInt32(page) - 1;
int pageSize = rows;
int totalRecords = products.Count();
int totalPages = (int)Math.Ceiling((float)totalRecords / (float)pageSize);
var data = products.OrderBy(x => x.Id)
.Skip(pageSize * (page - 1))
.Take(pageSize).ToList();
var jsonData = new
{
total = totalPages,
page = page,
records = totalRecords,
rows = data
};
return Json(jsonData, JsonRequestBehavior.AllowGet);
}
并将此标签添加到目标页面
<table id="jqGrid"></table>
<div id="jqGridPager"></div>
在脚本部分之后,添加以下内容:
<script>
var myGrid = $('#jqGrid');
myGrid.jqGrid({
url: '/Home/GetProducts/',
datatype: "json",
contentType: "application/json; charset-utf-8",
mtype: 'GET',
colNames: ['ProductID', 'Name', 'Price', 'Department', 'Action'],
colModel: [
{ name: 'Id', key: true, width: 75 },
{ name: 'Name', key: true, width: 200 },
{ name: 'Price', key: true, width: 75 },
{ name: 'Department', key: true, width: 200 },
{ name: 'Edit', key: true, width: 100, editable: true, formatter: editButton }
],
rowNum: 4,
pager: '#jqGridPager',
gridview: true,
rownumbers: true,
pagerpos: 'center'
});
</script>
原始帖子为here