Question

我从这个网站的帮助中得到了2个查询，它们是：

SELECT gr.g_name, (DATEDIFF(d, r.res_checkout_date, r.res_checkin_date) * pp.rate ) + ISNULL(i.inv_amount, 0)
FROM guest_reservation gr LEFT OUTER JOIN invoice i ON gr.confirm_no = i.confirm_no
JOIN reservation r ON gr.confirm_no = r.confirm_no
JOIN price_plan pp ON r.price_plan = pp.price_plan;

SELECT g.g_name, DATEDIFF(d, r.res_checkin_date, r.res_checkout_date)*p.rate+coalesce(i.inv_amount, 0) as Amount
FROM reservation as r  INNER JOIN priceplan as p
ON r.price_plan = p.price_plan
INNER JOIN guest_reservation as g
ON r.confirm_no = g.confirm_no
LEFT OUTER JOIN invoice as i
ON r.confirm_no = i.confirm_no;

所有表格都包含以下数据：

guest reservation表包含以下带有数据的列：

(confirm_no, agent_id, g_name, g_phone)

reservation表包含以下带有数据的列：

(confirm_no, credit_card_no, res_checkin_date, res_checkout_date, 
 default_villa_type, price_plan)

我需要以某种方式添加来自dining_order表的客人已订购的商品（与r_confirm_no表中的dining_order相关联等于来自confirm_no的{{1}} reservation表格），商品价格必须从dining_menu表格中获取（dining_order.item等于dining_menu.item）并添加到上述查询中。

我需要添加的新信息的关联表是：

invoice表包含以下带有数据的列：

(inv_no, inv_date, inv_amount, confirm_no).

price plan表包含以下带有数据的列：

(price_plan, rate, default_villa_type, bed_type)

Answer 1

这是未经测试的，但您可以使用子查询对每位客人的餐饮项进行求和，并将其添加到总数中。这也是一个外部连接，因为客人可能没有使用餐饮设施。

SELECT gr.g_name, (DATEDIFF(d, r.res_checkout_date, r.res_checkin_date) * pp.rate ) + ISNULL(i.inv_amount, 0) + ISNULL(d.total_dining, 0)
FROM guest_reservation gr 
LEFT OUTER JOIN invoice i ON gr.confirm_no = i.confirm_no
JOIN reservation r ON gr.confirm_no = r.confirm_no
JOIN price_plan pp ON r.price_plan = pp.price_plan
LEFT OUTER JOIN (SELECT r_confirmation_no, SUM(price) AS total_dining
                 FROM dining_order do JOIN dining_menu dm ON do.item = dm.item 
                 GROUP BY r_confirmation_no) AS d ON d.r_confirmation_no = r.confirm_no

SQL查询帮助Pt。 III（最后）

1 个答案: