我想将标题字符串转换为字典。字符串来自各种来源,因此格式有点复杂。
这是一个示例:
import ast
import re
header="{'Content-Type': 'text/html', 'Content-Security-Policy': "default-src 'self'; img-src 'self' https://www.google.com/ https://www.google-analytics.com/ https://stats.g.doubleclick.net/; form-action 'self' https://agilemail.createsend.com/ https://www.createsend.com/t/subscribeerror https://www.createsend.com/t/securedsubscribe; frame-src https://www.youtube-nocookie.com/; connect-src 'self'", 'X-Content-Type-Options': 'nosniff', 'X-Amz-Cf-Id': 'XZOj8R9YBVEMbHv93beUYFIizxUbrGKL_LVrS1gjMF-86I8mgtNFYw=='}"
headerDict = ast.literal_eval(header)
运行它时,出现此错误:
SyntaxError: invalid syntax
我将字符串"default-src [...] https://a.1password.eu/"
中的两个双引号从"
更改为""
但是仍然存在错误。显然是从'self'
的内容开始,其中包含单引号。
我完全不应该更改标题内容。但是,例如,如果我应用一条规则,则将每个"
替换为""
,这是可行的解决方案。由于我需要解析标题。它应该保留其原始数据,我不应该对其进行任何更改。
在这种情况下,解决方案是什么?这是一个示例,但我希望看到其他变体。如何将类似dict的字符串转换成字典?
答案 0 :(得分:2)
使用三引号引起来的字符串:
import ast
header = """{'Content-Type': 'text/html', 'Content-Security-Policy': "default-src 'self'; img-src 'self' https://www.google.com/ https://www.google-analytics.com/ https://stats.g.doubleclick.net/; form-action 'self' https://agilemail.createsend.com/ https://www.createsend.com/t/subscribeerror https://www.createsend.com/t/securedsubscribe; frame-src https://www.youtube-nocookie.com/; connect-src 'self'", 'X-Content-Type-Options': 'nosniff', 'X-Amz-Cf-Id': 'XZOj8R9YBVEMbHv93beUYFIizxUbrGKL_LVrS1gjMF-86I8mgtNFYw=='}"""
ast.literal_eval(header)
输出:
{'Content-Type': 'text/html',
'Content-Security-Policy': "default-src 'self'; img-src 'self' https://www.google.com/ https://www.google-analytics.com/ https://stats.g.doubleclick.net/; form-action 'self' https://agilemail.createsend.com/ https://www.createsend.com/t/subscribeerror https://www.createsend.com/t/securedsubscribe; frame-src https://www.youtube-nocookie.com/; connect-src 'self'",
'X-Content-Type-Options': 'nosniff',
'X-Amz-Cf-Id': 'XZOj8R9YBVEMbHv93beUYFIizxUbrGKL_LVrS1gjMF-86I8mgtNFYw=='}