COUNT在Sequelize生成的SELECT语句中出现在错误的位置

Question

我使用Sequelize想到了这段代码：

if(AFormName = 'xxx1') then
begin
    MyClass := MyClass1.Create;
end else if(AFormName = 'xxx2') then        
begin
    MyClass := MyClass2.Create;
end;

它生成此SQL：

    const users = db.Manager.findAll({
          attributes: ['managerid', 'managername', 'email'],
          include: [{
            model: db.Team,
            as: 'teams',
            attributes: ['teamid', 'teamname'],
          }, {
            model: db.Employee,
            as: 'employees',
            attributes: ['id', [sequelize.fn('COUNT', sequelize.col('employees.id')) ,'employee_count']]
          }],
          where: whereClause,
          order: orderClause,
          offset,
          limit,
          group: ['Manager.id', 'Manager.name', 'Manager.email']
        });

这不是我想要的。我希望有这样的东西：

SELECT "Manager".*, 
       "teams"."id" AS "teams.id", 
       "teams"."name" AS "teams.name", 
       "teams->TeamManager"."id" AS "teams.TeamManager.id", 
       "teams->TeamManager"."Manager_id" AS "teams.TeamManager.ManagerId", 
       "teams->TeamManager"."team_id" AS "teams.TeamManager.teamId", 
       "employees"."id" AS "employees.id", 
       COUNT("employees"."id") AS "employees.employee_count", 
       "employees->EmployeeManager"."id" AS "employees.EmployeeManager.id", 
       "employees->EmployeeManager"."Manager_id" AS "employees.EmployeeManager.ManagerId", 
       "employees->EmployeeManager"."Employee_id" AS "employees.EmployeeManager.EmployeeId" 
FROM (SELECT "Manager"."id", 
             "Manager"."name", 
             "Manager"."email"
      FROM "Managers" AS "Manager" 
      GROUP BY "Manager"."id", 
               "Manager"."name",
               "Manager"."email"
      LIMIT 20 OFFSET 0) AS "Manager" 
      LEFT OUTER JOIN ( "team_managers" AS "teams->TeamManager" 
      INNER JOIN "teams" AS "teams" ON "teams"."id" = "teams->TeamManager"."team_id") ON "Manager"."id" = "teams->TeamManager"."manager_id" 
      LEFT OUTER JOIN ( "employee_managers" AS "employees->EmployeeManager" 
      INNER JOIN "employees" AS "employees" ON "employees"."id" = "employees->EmployeeManager"."Employee_id") ON "Manager"."id" = "employees->EmployeeManager"."manager_id";

就我所追求的而言，此SQL可能并不完全正确，但是我想要的是将 SELECT "Manager".*, "teams"."id" AS "teams.id", "teams"."name" AS "teams.name", "teams->TeamManager"."id" AS "teams.TeamManager.id", "teams->TeamManager"."Manager_id" AS "teams.TeamManager.ManagerId", "teams->TeamManager"."team_id" AS "teams.TeamManager.teamId", "employees"."id" AS "employees.id", COUNT("employees"."id") AS "employees.employee_count", "employees->EmployeeManager"."id" AS "employees.EmployeeManager.id", "employees->EmployeeManager"."Manager_id" AS "employees.EmployeeManager.ManagerId", "employees->EmployeeManager"."Employee_id" AS "employees.EmployeeManager.EmployeeId" FROM ("managers") AS "Manager" LEFT OUTER JOIN ( "team_managers" AS "teams->TeamManager" INNER JOIN "teams" AS "teams" ON "teams"."id" = "teams->TeamManager"."team_id") ON "Manager"."id" = "teams->TeamManager"."manager_id" LEFT OUTER JOIN ( "employee_managers" AS "employees->EmployeeManager" INNER JOIN "employees" AS "employees" ON "employees"."id" = "employees->EmployeeManager"."Employee_id") ON "Manager"."id" = "employees->EmployeeManager"."manager_id"; GROUP BY "Manager"."id", "Manager"."name", "Manager"."email" LIMIT 20 OFFSET 0 中的COUNT包含在我的选择中。

我该怎么做？