Question

我正在通过使用javascript将西装对象数组和纸牌对象数组组合在一起来创建一副纸牌（纸牌对象数组）。

我正在使用forEach循环遍历西装，并且嵌套的是卡片的映射循环。

console.log返回正确的对象以推送到新数组，但是.push（）仅使用最后一个花色和最后一个卡来添加组合的对象。

我在哪里出错呢？

我尝试了多种不同的循环和方法来附加到新数组中而没有运气。 Console.log（）返回正确的值，但是我无法将正确的组合对象推入新数组。

  // Deck of Cards
var suits = [
  { suit: "clubs", color: "black" },
  { suit: "spades", color: "black" },
  { suit: "hearts", color: "red" },
  { suit: "diamonds", color: "red" }
];

var family = [
  { name: "2", value: 2 },
  { name: "3", value: 3 },
  { name: "4", value: 4 },
  { name: "5", value: 5 },
  { name: "6", value: 6 },
  { name: "7", value: 7 },
  { name: "8", value: 8 },
  { name: "9", value: 9 },
  { name: "10", value: 10 },
  { name: "J", value: 10 },
  { name: "Q", value: 10 },
  { name: "K", value: 10 },
  { name: "A", value: 1 },
];

var deck = new Array();

suits.forEach(function (x) {
  var arr = family.map((y) => {
    var obj = Object.assign(x, y);
    console.log(obj);
    deck.push(obj);
    return obj;
  });
  
  console.log(arr);
});

console.log(deck);

Answer 1

尝试使用Object.assign({}, x, y)代替Object.assign(x, y)。当前，您正在通过将y的所有属性添加到x中来操纵它。

// Deck of Cards
var suits = [
    {suit: "clubs",color: "black"},
    {suit: "spades",color: "black"},
    {suit: "hearts",color: "red"},
    {suit: "diamonds",color: "red"}    
];

var family = [
    {name: "2",value: 2},
    {name: "3",value: 3},
    {name: "4",value: 4},
    {name: "5",value: 5},
    {name: "6",value: 6},
    {name: "7",value: 7},
    {name: "8",value: 8},
    {name: "9",value: 9},
    {name: "10",value: 10},
    {name: "J",value: 10},
    {name: "Q",value: 10},
    {name: "K",value: 10},
    {name: "A",value: 1},
];

var deck = new Array();

suits.forEach(function(x){

    var arr = family.map( (y) => {
        var obj = Object.assign({}, x, y); 
        deck.push(obj);
        return obj; 
    });

});

console.log(deck);

Answer 2

Object.assign(x,y)将y的值放到x上。您希望不理会x，因此请使用Object.assign({}, x,y)将属性存储在新对象中。请看下面的演示：

var suits = [
    {suit: "clubs",color: "black"},
    {suit: "spades",color: "black"},
    {suit: "hearts",color: "red"},
    {suit: "diamonds",color: "red"}    
];

var family = [
    {name: "2",value: 2},
    {name: "3",value: 3},
    {name: "4",value: 4},
    {name: "5",value: 5},
    {name: "6",value: 6},
    {name: "7",value: 7},
    {name: "8",value: 8},
    {name: "9",value: 9},
    {name: "10",value: 10},
    {name: "J",value: 10},
    {name: "Q",value: 10},
    {name: "K",value: 10},
    {name: "A",value: 1},
];

const tmp = suits.reduce((acc, s) => {
  return acc.concat(family.map(f => {
    return Object.assign({}, f, s);
  }));
}, []);

const pre = document.createElement("pre");
pre.innerHTML = JSON.stringify(tmp, null, 4);
document.body.appendChild(pre);

Answer 3

如果使用you can use flatmap，则可以使其变得非常简单：

const suits = [{ suit: "clubs", color: "black" }, { suit: "spades", color: "black" }, { suit: "hearts", color: "red" }, { suit: "diamonds", color: "red" }]
const family = [{ name: "2", value: 2 }, { name: "3", value: 3 }, { name: "4", value: 4 }, { name: "5", value: 5 }, { name: "6", value: 6 }, { name: "7", value: 7 }, { name: "8", value: 8 }, { name: "9", value: 9 }, { name: "10", value: 10 }, { name: "J", value: 10 }, { name: "Q", value: 10 }, { name: "K", value: 10 }, { name: "A", value: 1 }]

const deck = suits.flatMap(s => family.map(f => ({...s, ...f})))

console.log(deck)

旁注，订购西服棍棒/钻石/心形/黑桃似乎有很强的约定（大概是布里奇的）。用英语很容易记住，因为它们是字母。

将两个数组中的2个对象组合成一个循环？

3 个答案: