MYSQL选择*唯一ID，其中char！= A

Question

|id|___|char|
|12|___|  A |
|57|___|  B |
|12|___|  C |

我想选择所有不同的id值！= A ...

我的查询给了我57和12，这是正确的...但是我不想要12 | C，因为它还有另外一对与之相关的12 | A ....

如果ID为'12'的行与A有任何关系，我该如何选择不选择其他所有具有不同值的ID'12'的行？

Answer 1

SELECT DISTINCT id FROM table WHERE id NOT IN (SELECT id FROM table WHERE char = 'A')

Answer 2

SELECT DISTINT id 
FROM table 
WHERE id NOT IN (SELECT id FROM table WHERE char = 'A')

Answer 3

尝试一下

SELECT DISTINCT ID,Char
FROM your_table
WHERE ID NOT IN
(
    SELECT DISTINCT ID 
    FROM your_table
    WHERE CHAR = 'A'
)

Answer 4

SELECT DISTINT id,Char FROM table WHERE char != 'A'

Answer 5

使用group by：

select id
from t
group by id
having sum( char = 'A' ) = 0;