我已经看过一些在Stackoverflow上创建字母数字ID的方法,但是它们都有缺点,一些方法没有检查冲突,而其他方法则使用了序列,这在使用逻辑复制时不是一个好选择。
经过一次谷歌搜索,我发现this网站上有以下脚本,该脚本检查冲突并且不使用序列。但是,当将行插入表中时,这是作为触发器完成的。
-- Create a trigger function that takes no arguments.
-- Trigger functions automatically have OLD, NEW records
-- and TG_TABLE_NAME as well as others.
CREATE OR REPLACE FUNCTION unique_short_id()
RETURNS TRIGGER AS $$
-- Declare the variables we'll be using.
DECLARE
key TEXT;
qry TEXT;
found TEXT;
BEGIN
-- generate the first part of a query as a string with safely
-- escaped table name, using || to concat the parts
qry := 'SELECT id FROM ' || quote_ident(TG_TABLE_NAME) || ' WHERE id=';
-- This loop will probably only run once per call until we've generated
-- millions of ids.
LOOP
-- Generate our string bytes and re-encode as a base64 string.
key := encode(gen_random_bytes(6), 'base64');
-- Base64 encoding contains 2 URL unsafe characters by default.
-- The URL-safe version has these replacements.
key := replace(key, '/', '_'); -- url safe replacement
key := replace(key, '+', '-'); -- url safe replacement
-- Concat the generated key (safely quoted) with the generated query
-- and run it.
-- SELECT id FROM "test" WHERE id='blahblah' INTO found
-- Now "found" will be the duplicated id or NULL.
EXECUTE qry || quote_literal(key) INTO found;
-- Check to see if found is NULL.
-- If we checked to see if found = NULL it would always be FALSE
-- because (NULL = NULL) is always FALSE.
IF found IS NULL THEN
-- If we didn't find a collision then leave the LOOP.
EXIT;
END IF;
-- We haven't EXITed yet, so return to the top of the LOOP
-- and try again.
END LOOP;
-- NEW and OLD are available in TRIGGER PROCEDURES.
-- NEW is the mutated row that will actually be INSERTed.
-- We're replacing id, regardless of what it was before
-- with our key variable.
NEW.id = key;
-- The RECORD returned here is what will actually be INSERTed,
-- or what the next trigger will get if there is one.
RETURN NEW;
END;
$$ language 'plpgsql';
我有一个已经包含数据的表,我添加了一个名为pid
的新列,是否有可能对其进行修改并使用函数调用作为默认值,以便所有先前的数据都获得一个简短的ID? / p>
答案 0 :(得分:2)
假设您有一个表test
:
DROP TABLE IF EXISTS test;
CREATE TABLE test (foo text, bar int);
INSERT INTO test (foo, bar) VALUES ('A', 1), ('B', 2);
您可以在其中添加一个id
列:
ALTER TABLE test ADD COLUMN id text;
并附加触发器:
DROP TRIGGER IF EXISTS unique_short_id_on_test ON test;
CREATE TRIGGER unique_short_id_on_test
BEFORE INSERT ON test
FOR EACH ROW EXECUTE PROCEDURE unique_short_id();
现在创建一个临时表temp
,其结构与测试相同(但没有数据):
DROP TABLE IF EXISTS temp;
CREATE TABLE temp (LIKE test INCLUDING ALL);
CREATE TRIGGER unique_short_id_on_temp
BEFORE INSERT ON temp
FOR EACH ROW EXECUTE PROCEDURE unique_short_id();
将test
倒入temp
:
INSERT INTO temp (foo, bar)
SELECT foo, bar
FROM test
RETURNING *
产生类似:
| foo | bar | id |
|------------+-----+----------|
| A | 1 | 9yt9XQwm |
| B | 2 | LCeiA-P8 |
如果其他表在test
表上具有外键引用,或者test
必须保持在线状态,
可能无法删除test
并将temp
重命名为test
。
相反,使用test
中的id
s更新temp
是更安全的。
假设test
有一个主键(为具体起见,我们称它为testid
),然后
您可以使用以下方式使用test
中的id
s个来更新temp
:
UPDATE test
SET id = temp.id
FROM temp
WHERE test.testid = temp.testid;
然后,您可以放下temp
表:
DROP TABLE temp;