将n x m numpy数组作为args传递给Thread对象会将其视为n个参数

Question

标题基本上说明了一切。如果您在Python 3.6.5中运行此代码：

from threading import Thread
import numpy as np 
import time

# function doesn't return anything
def do_stuff(x):
    x += 5

x = np.random.randint(256, size=(100,100), dtype=np.uint8)
Thread(target=do_stuff, args=(x), name="my thread").start()

time.sleep(1)

您收到以下错误：

Exception in thread my thread:
Traceback (most recent call last):
  File "/home/username/anaconda3/lib/python3.6/threading.py", line 916, in _bootstrap_inner
    self.run()
  File "/home/username/anaconda3/lib/python3.6/threading.py", line 864, in run
    self._target(*self._args, **self._kwargs)
TypeError: do_stuff() takes 1 positional argument but 100 were given

由于某种原因，numpy数组似乎正在扩展，这对我来说是极其出乎意料的行为。有人可以解释为什么会这样吗，并给我一个解决方法吗？

谢谢！