Question

我的表table_1的数据如下：

| WordID| Add  |
+-------+------+
|   1   | Hello| 
|   2   | Hi   | 
|   3   | Go   |
|   4   | Come |

我有一个字符串“你好，请到约翰家。”

我想删除问候并使用SQL Server从字符串中查找，输出结果应为

", Please to John's House"

我该怎么办？

Answer 1

我正在使用克里斯莫里斯（Chris Morris）创建的函数，该函数由Dwain Camps在here中进行了解释。

我更改了字符串以测试误报。

declare @list varchar(255) = 'Hello, Please Go to Phillip''s House who left long ago.';

create table table_1(WordID int, [Add] varchar(255));
insert into table_1(WordID, [Add]) values
(1,   'Hello'), 
(2,   'Hi'), 
(3,   'Go'),
(4,   'Come');


SELECT ( SELECT Item + ''
            FROM dbo.PatternSplitCM(@list, '%[^a-zA-Z'']%') ps
            WHERE NOT EXISTS( SELECT * FROM table_1 t WHERE ps.Item = t.[Add])
            ORDER BY ItemNumber
            FOR XML PATH(''), TYPE).value('./text()[1]', 'varchar(max)')

函数定义在这里：

-- PatternSplitCM will split a string based on a pattern of the form 
-- supported by LIKE and PATINDEX 
-- 
-- Created by: Chris Morris 12-Oct-2012 
CREATE FUNCTION [dbo].[PatternSplitCM]
(
       @List                VARCHAR(8000) = NULL
       ,@Pattern            VARCHAR(50)
) RETURNS TABLE WITH SCHEMABINDING 
AS 
RETURN
    WITH numbers AS (
      SELECT TOP(ISNULL(DATALENGTH(@List), 0))
       n = ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
      FROM
      (VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) d (n),
      (VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) e (n),
      (VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) f (n),
      (VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) g (n))
    SELECT
      ItemNumber = ROW_NUMBER() OVER(ORDER BY MIN(n)),
      Item = SUBSTRING(@List,MIN(n),1+MAX(n)-MIN(n)),
      [Matched]
     FROM (
      SELECT n, y.[Matched], Grouper = n - ROW_NUMBER() OVER(ORDER BY y.[Matched],n)
      FROM numbers
      CROSS APPLY (
          SELECT [Matched] = CASE WHEN SUBSTRING(@List,n,1) LIKE @Pattern THEN 1 ELSE 0 END
      ) y
     ) d
     GROUP BY [Matched], Grouper;

Answer 2

您需要对该表进行（伪）更新：

declare @list varchar(255) = 'Hello, Please Go to John''s House.';

create table table_1(WordID int, [Add] varchar(255));
insert into table_1(WordID, [Add]) values
(1,   'Hello'), 
(2,   'Hi'), 
(3,   'Go'),
(4,   'Come');

update table_1
set @list = replace(@list, [Add], '');

select @list;

结果：

, Please  to John's House.

从SQL Server中的字符串中删除单词列表

2 个答案: