获取多个复选框的1或0值，取决于是否已选中它们

Question

我想从多个复选框中获取1或0的值，具体取决于是否已选中它们。

我有几行字段

activity    duration [checkbox] date
activity    duration [checkbox] date
activity    duration [checkbox] date
activity    duration [checkbox] date

<select name="activities[]">
    <option value="12">Football</option>
</select>
<input type="text" name="duration[]" placeholder="" /> 
<input type="checkbox" name="is_distance[]" value="1">
<input type="text" class="datepicker" name="datepicker[]" id="">

当字段包含内容时，它们将看起来像这样

Football   90  1 2019-05-09
Cycling    120 0 2019-05-09
Cricket    70  0 2019-05-09
Basketball 90  1 2019-05-09

其中1是复选框已被选中。

我下面有获取值的代码。

foreach ( $_POST['activities'] as $key=>$value ) {
    $dist_activity_id = $_POST['activities'][$key];
    $dist_activity_duration = $_POST['duration'][$key];
    $dist_date = $_POST['datepicker'][$key];
    $dist_list_id = $list_id;

    if(isset($_POST['is_distance'][$key])) {
        $is_distance = $_POST['is_distance'][$key];
    } else {
        $is_distance = 0;
    }
}

输出不会将复选框的值保持在所选位置，而是将所有所选内容移到顶部。

Football   90  1 2019-05-09
Cycling    120 1 2019-05-09
Cricket    70  0 2019-05-09
Basketball 90  0 2019-05-09

有人可以帮忙吗？

if(isset($_POST['submit'])) {
if (count(array_filter($_POST['duration'])) == count($_POST['duration']) && count(array_filter($_POST['datepicker'])) == count($_POST['datepicker'])) {
    foreach ( $_POST['activities'] as $key=>$value ) {
        $dist_activity_id = $_POST['activities'][$key];
        $dist_activity_duration = $_POST['duration'][$key];
        $dist_date = $_POST['datepicker'][$key];

        if(isset($_POST['is_distance'][$key])) {
            $is_distance = $_POST['is_distance'][$key];
        } else {
            $is_distance = 0;
        }                           

        $dist_list_id = $list_id;
    }

}else {
    $alert = "<div class='alert alert-danger' role='alert'>Please enter required fields</div>";
}
}