Laravel搜索反复返回数据

Question

我使用此功能进行搜索，并且一遍又一遍地返回结果

控制器

function search(Request $request)
{
    $q = $request->input('searchinput');
    if($q != ''){
        $links = Link::where('status', '1')
           ->where('name','LIKE', "%{$q}%")
           ->orWhere('body','LIKE',"%{$q}%")
           ->paginate(6);
        if ($request->ajax()) {
          $view = (String) view('front.links.more',compact('links'));
          return response()->json(['html'=>$view]);
        }
        return view('front.search.index', compact('links', 'q'))->withQuery($q);
    }else{
        Session::flash('warning', 'You need to fill search field.');
        return redirect()->back();
    }
}

表格

<form class="form-inline" action="{{route('searchin')}}">
  @csrf
  <input class="form-control mr-sm-2" type="search" placeholder="Search" aria-label="Search" name="searchinput">
</form>

路线

Route::any('search', 'Front\SearchController@search')->name('searchin');

JavaScript

<script defer>
        $(function(){
            var page = 1;
            loadMoreData(page);
            function loadMoreData(page){
                var isotopShowmoreJs = $('.LOADBTN'),ttAddItem = $('.tt_job_listing');

                if (isotopShowmoreJs.length && ttAddItem.length) {
                    isotopShowmoreJs.on('click', function(e) {
                        page++;
                        e.preventDefault();
                        $.ajax({
                            url: '?page=' + page,
                            type: "get",
                            beforeSend: function(){
                                $('.ajax-load').show();
                                $('.spinner-border').show();
                            }
                        }).done(function(data){
                            if(data.html == ""){
                                $('.LOADBTN').hide();
                                $('.spinner-border').hide();
                                $('.tt_item_all_js').css('display', "block");
                            }
                            var $item = $(data.html);
                            ttAddItem.append($item);
                            adjustOffset();
                        }).fail(function(jqXHR, ajaxOptions, thrownError){
                            alert('server not responding...');
                            $('.spinner-border').hide();
                            $('.LOADBTN').hide();
                        });

                        function adjustOffset(){
                            var offsetLastItem = ttAddItem.children().last().children().offset().top - 80;
                            var $body = $('body');
                            var $html = $('html');
                            $($body, $html).animate({scrollTop: offsetLastItem}, 500);
                            $('.spinner-border').hide();
                        };
                        return false;
                    });
                };
            }
        });
    </script>

屏幕截图

视频

https://streamable.com/qwh34

有什么主意吗？

更新为Aditya Thakur条评论

网络

控制台console.log(page++);

控制台console.log(page);

更新2

dd($request->all());

array:2 [▼
  "_token" => "eNio8rDaCL2du4I7KAzt5UU3ukrvHHnco3x2orUp",
  "searchinput" => "test"
]

dd($request->ajax());返回true

dd($request->input('page'));返回null

更新3

Dan's response

删除控制器中的条件是否删除了第二个ajax请求并修复了某些部分。

Sandeep Sudhakaran响应，

这是删除if条件后的最新结果。 PS：我标记了重复的数据。

更新4

加载按钮

@if(count($results)>0)
            <div class="row">
                <div class="col-md-12 mt-5 mb-5 text-center">
                    <div class="row">
                        <div class="col-12 text-center">
                            <a href="#" class="btn btn-primary LOADBTN">
                                <div class="spinner-border" style="display: none;" role="status">
                                  <span class="sr-only">{{__('links.loading')}}</span>
                                </div>
                                {{__('links.loadmore')}}
                            </a>
                            <div class="tt_item_all_js" style="display:none;">
                                <button type="button" class="btn btn-secondary btn-3" disabled>{{__('links.nomore')}}</button>
                            </div>
                        </div>
                    </div>
                </div>
            </div>
            @endif

Answer 1

按如下所示更改ajax调用。

$.ajax({ 
url: '', 
data:{'page':page}
type: "get", 
beforeSend: function(){ 
    $('.ajax-load').show(); 
    $('.spinner-border').show(); 
})