正则表达式查找多个单词

Question

正则表达式，使用正则表达式从多行中查找与A23 Z 12345完全相同的文本。如果发现以上结果，则为TRUE。

输入：

For the following policy A23 Z 12345 will be cancelled.

预期输出：

A23 Z 12345

Answer 1

精确捕获的表达非常简单。您可能只想在其周围添加一个捕获组而没有任何其他边界，它会这样做：

(A23 Z 12345)

如果愿意，可以使用this tool测试/编辑/更新/更改该表达式。如果需要，可以为其添加更多边界。

RegEx描述图

此图显示了表达式的工作方式，您可以在此link中可视化其他表达式：

const regex = /(A23 Z 12345)/gm;
const str = `Any other chars that might be A23 Z 12345 and any other chars after A23 Z 12345 Any other chars that might be A23 Z 12345 and any other chars after A23 Z 12345 Any other chars that might be A23 Z 12345 and any other chars after A23 Z 12345 `;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

性能测试

此JavaScript代码段使用简单的100万次for循环来显示该表达式的性能。

const repeat = 1000000;
const start = Date.now();

for (var i = repeat; i >= 0; i--) {
	const string = 'Any other chars that might be A23 Z 12345 and any other chars after';
	const regex = /(.*)(A23 Z 12345)(.*)/gm;
	var match = string.replace(regex, "$2");
}

const end = Date.now() - start;
console.log("YAAAY! \"" + match + "\" is a match  ");
console.log(end / 1000 + " is the runtime of " + repeat + " times benchmark test.  ");

Answer 2

使用re库解决此问题的Python解决方案：

x = 'For the following policy A23 Z 12345 will be cancelled.  A23 Z 123456r will be cancelled.'
print(re.findall('A23 Z 12345', x))

['A23 Z 12345', 'A23 Z 12345']