Question

即使if条件为deck()，if语句也不会在True函数中执行。

我总是在问输入变量中输入字母，该变量总是退出in机密或random_word，例如，如果random_word是“ AAF”，则我会传递问值“ A”还是“ F“

import random
random_word = random.choice(open('sowpods.txt','r').read().split())
secret = [x for x in random_word]
print('secret: ', secret)
place = [' ' for x in range(len(random_word))]
print('place: ', place)
guessed = list()
chance = 0
play = True
print("Welcome to Hangman Game!")
print(random_word)

def board():

    ask = input("Please guess the letter: ").upper

    if ask in secret:
        return("ask in secret")
    else:
        print('ask not in secret')

board()

输出：

secret:  ['P', 'O', 'U', 'S', 'S', 'I', 'E']
place:  [' ', ' ', ' ', ' ', ' ', ' ', ' ']
Welcome to Hangman Game!
POUSSIE
Please guess the letter: P
ask not in secret

我要执行if语句而不是else语句

Answer 1

输入后打印出ask（打印出或检查异常的变量通常应该是您的第一步调试步骤）：

ask = input("Please guess the letter: ").upper
print(ask) # add this

如果这样做，您应该立即看到问题：

<built-in method upper of str object at 0x7f977c1da3e8>
          ^^^^^^^^^^^^

这是一个函数对象，而不是预期的字符串，这是因为您缺少了 call （而不是仅引用）{{ 1}}函数。应该是：

upper

Answer 2

.upper方法需要使用方括号和print（“秘密询问”）而不是return（“秘密询问”）

random_word = random.choice(open('sowpods.txt','r').read().split())
secret = [x for x in random_word]
print('secret: ', secret)
place = [' ' for x in range(len(random_word))]
print('place: ', place)
guessed = list()
chance = 0
play = True
print("Welcome to Hangman Game!")
print(random_word)

def board():

    ask = input("Please guess the letter: ").upper()

    if ask in secret:
        print("ask in secret")
    else:
        print('ask not in secret')

board()

如果条件中没有条件，则语句未在函数内执行

2 个答案: