Question

因此，我试图将用户输入的中间名切开并打印出来，但是它不起作用，我不知道该怎么做。

我已经尝试过查找

name_amount = int(input("How many names do you have? "))
namelist = []
index = 0
for i in range (name_amount):
    name = input("Name: ")
    namelist.append(name)
    index += 1
print "You have " + str (name_amount) + " names."
print "Middle names: " + namelist[0][1:index - 1]

例如，如果您说您有3个名字，然后说L，然后T，然后K，我想说

Middle names: T

但是它只是说：

Middle names:

然后没有其他内容。

Answer 1

为什么不只是：

name_amount = int(input("How many names do you have? "))
namelist = []
index = 0
for i in range (name_amount):
    name = input("Name: ")
    namelist.append(name)
    index += 1
print "You have " + str (name_amount) + " names."
try:
    print "Middle names: " + namelist[1]
except:
    print "No middle names found"

更改：

print "Middle names: " + namelist[0][1:index - 1]

收件人：

try:
    print "Middle names: " + namelist[1]
except:
    print "No middle names found"

就是这样，它将起作用...

Answer 2

您应该进行更改以返回列表中的第二个元素，并添加一个健全性检查，以发现是否首先输入了两个以上的名称。

name_amount = int(input("How many names do you have? "))
namelist = []
index = 0
for i in range (name_amount):
    name = input("Name: ")
    namelist.append(name)
    index += 1
print "You have " + str (name_amount) + " names."

# Checking if at least 2 names are entered
if name_amount > 2:
    print "Middle names: " + namelist[1]
else: 
    print "Could not find a middle name"

与python codehs 8.4.4混淆

2 个答案: