Question

我正在编写一个跳棋游戏。我有一个CBoard类，它具有指向CGamePieces和CTiles的两个指针向量。第一次绘制木板时，它可以完美绘制。如果我尝试对矢量进行任何修改并再次绘制，则会重新绘制原始板，而不会反映出更改。

这是我向这些向量添加元素的方式：

void CBoard::getPieces()
{
    while(mGamePieces.size() < 12)
    {
        shared_ptr<CWhitePiece> white(new CWhitePiece());
        white->setBoard(this);
        white->setTile(mTiles[tileIndex]);
        mGamePieces.push_back(white);
    }
}

要绘制电路板，我要遍历所有看起来像这样的矢量，从而在所有CTiles和CGamePieces上调用Draw函数：

void CGamePiece::Draw(Gdiplus::Graphics * graphics)
{
    double wid = 100;
    double hit = 100;
    graphics->DrawImage(mImage.get(),
        float(mTile->getColumn() / 2) + 100 * mTile->getColumn(), float(mTile->getRow() / 2) + 100 * mTile->getRow(),
        100.0, 100.0);
}

使用调试器，我看到正在迭代的向量具有反映的更改-如果删除某项，则少一个项目，如果添加某项，则该项目存在于向量中。重画电路板之前将调用此代码：

void CBoard::move()
{
    shared_ptr<CBrownPiece> brown(new CBrownPiece());
    brown->setBoard(this);
    brown->setTile(mTiles[30]);
    mGamePieces.push_back(brown);
}

由于调试时似乎对矢量进行了更改，因此我不确定为什么不会在屏幕上绘制此附加片段，尤其是当我看到在其上调用Draw函数时。如果通过在这些矢量的每一项上调用draw来绘制面板，那么是否应该从屏幕上绘制/删除添加到矢量中的项目？

点击一块时我会重画屏幕

/** 
 * When the mouse is pressed down, we will run the HitTest function.
 * If HitTest does not return a nullpointer, we will run the 
 * move function.
 */
void CChildView::OnLButtonDown(UINT nFlags, CPoint point)
{
    // Check if a piece has been clicked
    mClickedPiece = mBoard.HitTest(point.x, point.y);

    if (mClickedPiece != nullptr && !mClickedPiece->getClicked())
    {
        mClickedPiece->setClicked(true); // This will allow us to find the piece to move in the vector of CGamePieces
        mBoard.move();
        OnPaint();
        //mClickedPiece->setClicked(false);
    }
}

/** This function is called to draw in the window.
*
* This function is called in response to a drawing message
* whenever we need to redraw the window on the screen.
* It is responsible for painting the window.
*/
void CChildView::OnPaint()
{
    CPaintDC paintDC(this);     // device context for painting
    CDoubleBufferDC dc(&paintDC); // device context for painting
    Graphics graphics(dc.m_hDC);
    mBoard.OnDraw(&graphics);
}

首次正确显示GDI +仅绘制屏幕

0 个答案: