Question

客户名称在单词“ for”之后，并在括号（“”之前），该提案名称开始于提案编号。我需要提取客户名称，以便在以后的步骤中查找交易。最简单的方法是使用Zapier提取模式还是在Python中使用Zapier代码？

我已经尝试过了，但是没有用。看起来很有希望。

input_data

client =提醒：Leruths已向您发送了一个有关公司名称的提案（＃642931）

import regex
rgx = regex.compile(r'(?si)(?|{0}(.*?){1}|{1}(.*?)
{0})'.format('for', '('))
s1 = 'client'
for s in [s1]:
m = rgx.findall
for x in m:
print x.strip()

我也尝试过，但没有用。

start = mystring.find( 'for' )
end = mystring.find( '(' )
if start != -1 and end != -1:
result = mystring[start+1:end]

我正在寻找示例中要返回的商户名称。

Answer 1

最快的方式：

start = client.find('for')
end = client.find('(')
result = client[start+4:end-1]
print(result)

使用正则表达式：

result = re.search(r' for (.*) [(]', client)
print(result.group(1))

可能有一种更清洁的方法，但这是不使用正则表达式的另一种解决方案

client = "Reminder: Leruths has sent you a proposal for Business Name (#642931)"

cs = client.split(" ")
name = ""
append = False
for word in cs:
    if "for" == word:
        append = True
    elif word.startswith("("):
        append = False
    if append is True and word != "for":
        name += (word + " ")
name = name.strip()
print(name)

另一种方法：

client = "Reminder: Leruths has sent you a proposal for Business Name (#642931)"

cs = client.split(" ")
name = ""
forindex = cs.index("for")

for i in range(forindex+1, len(cs)):
    if cs[i].startswith("("):
        break
    name += cs[i] + " "
name = name.strip()

print(name)

运行以下代码将给出：

Regex method took 2.3912417888641357 seconds
Search word by word method took 4.78193998336792 seconds
Search with list index method took 3.1756017208099365 seconds
String indexing method took 0.8496286869049072 seconds

代码以最快的速度获得超过一百万次尝试的名称：

import re
import time

client = "Reminder: Leruths has sent you a proposal for Business Name (#642931)"

def withRegex(client):
    result = re.search(r' for (.*) [(]', client)
    return(result.group(1))

def searchWordbyWord(client):
    cs = client.split(" ")
    name = ""
    append = False
    for word in cs:
        if "for" == word:
            append = True
        elif word.startswith("("):
            append = False
        if append is True and word != "for":
            name += (word + " ")
    name = name.strip()
    return name

def searchWithListIndex(client):
    cs = client.split(" ")
    name = ""
    forindex = cs.index("for")

    for i in range(forindex+1, len(cs)):
        if cs[i].startswith("("):
            break
        name += cs[i] + " "
    name = name.strip()

    return name

def stringIndexing(client):
    start = client.find('for')
    end = client.find('(')
    result = client[start+4:end-1]
    return result

wr = time.time()
for x in range(1,1000000):
    withRegex(client)
wr = time.time() - wr
print("Regex method took " + str(wr) + " seconds")

sw = time.time()
for x in range(1,1000000):
    searchWordbyWord(client)
sw = time.time() - sw
print("Search word by word method took " + str(sw) + " seconds")

wl = time.time()
for x in range(1,1000000):
    searchWithListIndex(client)
wl = time.time() - wl
print("Search with list index method took " + str(wl) + " seconds")

si = time.time()
for x in range(1,1000000):
    stringIndexing(client)
si = time.time() - si
print("String indexing method took " + str(si) + " seconds")

在电子邮件主题行中的单词“ for”和左括号“（”之间提取单词。电子邮件主题行是输入

1 个答案: