我有一张叫Sale的桌子。我想检索每辆tab <- structure(list(Groups = c("Group1", "Group1", "Group1", "Group1",
"Group1", "Group2", "Group2", "Group2", "Group3", "Group3", "Group3",
"Group3"), Species = c("Sp1", "Sp1", "Sp2", "Sp3", "Sp4", "Sp2",
"Sp3", "Sp4", "Sp1", "Sp3", "Sp3", "Sp3"), Value = c(1L, 4L,
78L, NA, NA, 3L, 9L, 8L, 9L, 10L, 110L, 14L)),
class = "data.frame", row.names = c("1",
"2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"))
tab1 <- structure(list(Groups = c("Group1", "Group1", "Group1", "Group1",
"Group1", "Group2", "Group2", "Group2", "Group3", "Group3", "Group3",
"Group3"), Species = c("Sp1", "Sp1", "Sp2", "Sp3", "Sp4", "Sp2",
"Sp3", "Sp4", "Sp1", "Sp3", "Sp3", "Sp3"), Value = c(1L, 4L,
78L, NA, NA, 3L, 9L, 8L, 9L, 10L, 110L, 14L), sp = c(3L, 3L,
NA, 3L, 3L, 2L, 2L, NA, 2L, 3L, 3L, 2L), mrca = c(3L, 3L, NA,
12L, 3L, 3L, 40L, NA, 2L, 3L, 2L, 3L)),
class = "data.frame", row.names = c("1",
"2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12"))
汽车的最新销售记录。
type
我有一个MySQL查询,该查询为我提供了所需的结果,如下所示:
public class Sale {
private Long id,
private String make,
private String model,
private Integer year,
private String type, // sedan, suv, van, truck etc.
private Double price
}
我想使用Hibernate 5方法编写此查询。我在寻找类似于以下内容的代码。
SELECT s1.*
FROM sale s1 LEFT JOIN sale s2
ON (s1.type = s2.type AND s1.id < s2.id)
WHERE s2.id IS NULL;