Question

嘿伙计们，我想建立一个以学术为导向的配对网站，让男孩和女孩通过学业表现和爱好找到他们的潜在合作伙伴。

我只是考虑转换考试成绩的数量，例如。 A，B，C并将它们转换为S级，A级等联赛。首先，我想将考试成绩A转换为5的整数，将考试成绩B转换为4的整数，依此类推。然后我将它们总结并将它们分类到各自的类中。

原始和疲惫的代码......我不确定它是否会起作用。

$obtaindata = mysql_fetch_assoc(mysql_query('SELECT * FROM userinfo WHERE primaryemel="' . $_COOKIE['smkdtuser'] . '"'));

$pmrresults = json_decode($obtaindata['pmr']);
$spmresults = json_decode($obtaindata['spm']);
$upsresults = json_decode($obtaindata['upsr']);

function calculateClassForPMR ($pmrresults) {
$aquality = (int)$pmrresults['a'] * 5;
$bquality = (int)$pmrresults['b'] * 4;
$cquality = (int)$pmrresults['c'] * 3;
$dquality = (int)$pmrresults['d'] * 2;
$gquality = (int)$pmrresults['g'] * 1;

$additup = $aquality + $bquality + $cquality + $dquality + $gquality;

//Classify sum of scores to their respective class
if ($additup => 35) {$classified = "s";}
elseif ($additup >= 29 && $additup <= 34) {$classified = "a";}
elseif ($additup >= 23 && $additup <= 28) {$classified = "b";}
elseif ($additup >= 17 && $additup <= 22) {$classified = "c";}
elseif ($additup >= 11 && $additup <= 16) {$classified = "d";}
elseif ($additup >= 0 && $additup <= 10) {$classified = "e";}
else {$classified = "wtf";};

return $classified; }

不要怪我，我刚开始学习php并尝试做一些奇怪的事情......

非常感谢任何回复或评论。

Answer 1

当使用json_decode时，我假设你在该tabel行中有{"a":1,"b":2,"c":3,"d":4,"e":5}这样的东西。尝试使用：

$pmrresults = var_dump(json_decode($obtaindata['pmr'], true))然后您可以使用$pmrresults['a'];

将值存储到DB

时，您必须json_encode()

I don't want to rent another server just to test it... it's costly. ...用户XAMPP可免费测试。

将考试成绩分类为联赛

1 个答案: