透视表并将结果与​​列的汇总合并

时间:2019-05-09 09:27:53

标签: sql sql-server

我有两个带有列的表:Sales_Margin:分支,项目代码,项目名称,销售数量,销售率,成本,保证金

目录: 垂直,项目ID,零件说明

我需要以这样的方式输出:“目录”表中“垂直”中的不同值是列,而“销售报告”表中的“分支”中是行。 我通过数据透视获得了这一部分:

我的代码:

select branch as Branch, [Vertical1], [Vertical2], [Vertical3], 
[Vertical4]
from 
( 
select branch, vertical, round((sum(margin)/sum([Sale Rate])),3) [Avg GM]
from
Sales_Margin JOIN Catalogue
ON Sales_Margin.[Item Code] = Catalogue.[ITEM ID]
group by branch, VERTICAL
) x
pivot
(
    sum([Avg GM]) 
        for vertical 
    in([Vertical1], [Vertical2], [Vertical3], [Vertical4])
) as pivot_table

但是我还需要“销售报告”表中“保证金”列的总和,以使保证金按分支分组(将输出复制为excel并采用百分比) 预期输出:

  Branch Vertical1 Vertical2 Vertical3  Vertical4       Margin
       A1       0%       9%       52%         0%       A1 Margin
       A2       40%      9%       66%         1%       A2 Margin    
       A3       32%      4%       57%         2%       A3 Margin    
       A4       17%      9%       65%         17%      A4 Margin    

我尝试使用相关的子查询,如下所示,但它不起作用:

select branch as Branch, [Vertical1], [Vertical2], [Vertical3], 
[Vertical4], 
(select sum(Margin) from Sales_Margin a where a.Branch = 
x.branch)
from 
(
select branch as Branch, [Vertical1], [Vertical2], [Vertical3], 
[Vertical4]
from 
( 
select branch, vertical, round((sum(margin)/sum([Sale Rate])),3) [Avg GM]
from
Sales_Margin JOIN Catalogue
ON Sales_Margin.[Item Code] = Catalogue.[ITEM ID]
group by branch, VERTICAL
) x
pivot
(
    sum([Avg GM]) 
    for vertical 
    in([Vertical1], [Vertical2], [Vertical3], [Vertical4])
) as pivot_table
) z

它说,

The multi-part identifier "x.branch" could not be bound.

有人可以让我知道如何获取按分支添加分组数值的保证金列

1 个答案:

答案 0 :(得分:0)

您需要使用z.branch,因为它引用了该外部子查询。