Question

我想从Android联系人中获取ID，名称，生日，地址。我更改了uri（ContactsContract.CommonDataKinds，ContactsContract.Contacts等），并能够获取地址，但是生日消失了。无论如何，我都找不到一次同时获取两者的解决方案。

  année: <select id="annee">
        <option value="">--année--</option>
        <option value="2019">2019</option>
        <option value="2020">2020</option>
        <option value="2021">2021</option>
        <option value="2022">2022</option>
        <option value="2023">2023</option>
        <option value="2024">2024</option>
    </select>
 <?php var_dump($this->input->post('annee'));
 var_dump($surcharges);
 ?>

以上代码的输出为：

public void getBirthdays() {

    // get data from contacts
    Uri uri = ContactsContract.Data.CONTENT_URI;

    String[] projection = new String[]{
            ContactsContract.CommonDataKinds.Event.CONTACT_ID,
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.CommonDataKinds.Event.START_DATE,
            ContactsContract.CommonDataKinds.StructuredPostal.FORMATTED_ADDRESS};

    String selection =
            ContactsContract.Data.MIMETYPE + "= ? AND " +
                    ContactsContract.CommonDataKinds.Event.TYPE + "=" + ContactsContract.CommonDataKinds.Event.TYPE_BIRTHDAY;

    String[] selectionArgs = new String[]{ContactsContract.CommonDataKinds.Event.CONTENT_ITEM_TYPE};

    Cursor cursor = getContentResolver().query(uri, projection, selection, selectionArgs, null);
    int columnCount = cursor.getColumnCount();
    cursor.moveToFirst();
    for (int i = 0; i < columnCount; i++) {
        Common.echo(cursor.getColumnName(i) + ", " + cursor.getString(i));
    }
    cursor.close();
}

“ data1”字段被列出两次，因为START_DATE（生日）和FORMATTED_ADDRESS都存储在同一虚拟列“ data1”中。

是否有一种方法可以在解析器中定义虚拟列名，例如与SQL等效的“ SELECT col1 AS name1，col2 AS name2，col3，col4 WHERE ...”？

Answer 1

两个问题：您将查询限制为仅EVENT s，并且只记录了查询中找到的第一行。

尝试一下：

private class Contact {
    public Long contactId;
    public String name;
    public String birthday;
    public String address;
}

public void getBirthdaysAndAddress() {

    // mapping from contactId to a contact object 
    Map<Long, Contact> contacts = new HashMap<>();

    Uri uri = Data.CONTENT_URI;

    String[] projection = new String[]{
            Data.CONTACT_ID,
            Data.DISPLAY_NAME,
            Data.MIMETYPE,
            Data.DATA1,
            Event.TYPE};

    // get ALL rows that represent either a birthday or a postal address
    String selection = Data.MIMETYPE + "=? OR " + Data.MIMETYPE + "=?";
    String[] selectionArgs = new String[]{Event.CONTENT_ITEM_TYPE, StructuredPostal.CONTENT_ITEM_TYPE};

    Cursor cursor = getContentResolver().query(uri, projection, selection, selectionArgs, null);

    while (cursor.moveToNext()) {
        Long id = cursor.getLong(0);

        // get an existing contact object, or create a new one
        Contact contact = contacts.get(id);
        if (contact == null) {
            contact = new Contact();
            contact.contactId = id;
            contact.name = cursor.getString(1);
            contacts.put(id, contact);
        }

        String mimetype = cursor.getString(2);
        if (mimetype.equals(Event.CONTENT_ITEM_TYPE)) {
            // this is an event row, check that it is a birthday
            int type = cursor.getInt(4);
            if (type == Event.TYPE_BIRTHDAY) {
                contact.birthday = cursor.getString(3);
            }
        } else {
            // this is an address row
            contact.address = cursor.getString(3);
        }
    }
    cursor.close();

    // print all contact objects containing a birthday
    Iterator it = mp.values().iterator();
    while (it.hasNext()) {
        Contact contact = (Contact) it.next();
        if (!TextUtils.isEmpty(contact.birthday)) {
            Log.i("Birthday contacts", contact.contactId + " - " + contact.name + " - " + contact.birthday + " - " + contact.address);
        }
    }
}

在一个查询中从android联系人获取地址和生日

1 个答案: