如何在列表理解中转换以下代码段

时间:2019-05-09 08:06:37

标签: python python-3.x list-comprehension

我用嵌套循环编写了一个方法,但是现在我想将其转换为列表理解,如何在列表理解中转换以下代码段

def A(results, required_result):
    """
    Args: 
         results (list) -- list of dicts
         required_result (str)
    Returns:
         list of strings and dict
         e.g.: ['a', {'key': 'value'}, 'b']
    """
    data = []
    for result in results:
        result = result[required_result].replace('\n', '').split('<br>')
        for res in result:
            if 'some_text' in res:
                carousel = create_carousel(res)
                data.append(carousel)
            else:
                data.append(res)
    return data

2 个答案:

答案 0 :(得分:3)

我不认为这比原始内容更具可读性,但是您可以:

data = [
    create_carousel(res) if 'some_text' in res else res
    for result in results
    for res in result[required_result].replace('\n', '').split('<br>')
]

答案 1 :(得分:2)

你在这里

output = [
    create_carousel(res)  if 'some text' in res else res #Making the if-condition choice and creating the object or keeping the item in the list
    for item in results #Iterating on results
    for res in item[required_result].replace('\n', '').split('<br>') #Create the temporary list after replace and split, and iterating on it
]