Question

我今晚开始尝试学习C ++，而现在我只是在IDE中搞乱。如何使这个简单的程序在您猜到正确的数字（5、6或7）之前不关闭程序？

按现状显示，只需输入一次，然后说按任意键关闭即可，而不是让我继续猜测。

#include <iostream>

int main() 
{
    int favorite_number;

    std::cout << "Enter your favorite number between 1 and 100: ";
    std::cin >> favorite_number;

        if(favorite_number == 5 || favorite_number == 6 || favorite_number == 7)
        {
        std::cout << "Amazing!! That's my favorite number too!";
        }

    std::cout << "Nice try, but that's not my favorite number" << std::endl;
    return 0;
}

Answer 1

感谢弄清楚了！

#include <iostream>

int main() 
{
    int favorite_number;
    bool completed = false;

    while(completed == false)
    {
    std::cout << "Enter your favorite number between 1 and 100: ";
    std::cin >> favorite_number;

        if(favorite_number == 5 || favorite_number == 6 || favorite_number == 7)
        {
        std::cout << "Amazing!! That's my favorite number too!";
        completed = true;
        return 0;
        }
        else
             std::cout << "Nice try, but that's not my favorite number" << std::endl;

        }


    return 0;
}

Answer 2

很高兴您找到了解决方案！此外，请查看以下代码：

int main() 
{
    int favorite_number;

    while(1)
    {
        std::cout << "Enter your favorite number between 1 and 100: ";
        std::cin >> favorite_number;

        if(5 == favorite_number || 6 == favorite_number || 7 == favorite_number)
        {
            std::cout << "Amazing!! That's my favorite number too!";
            return 0;
        }
        else
            std::cout << "Nice try, but that's not my favorite number" << std::endl;

    }
}

您可以使循环无限，而无需使用已完成的bool。只要插入的号码与收藏夹号码之一不同，它就可以运行。此外，代码中的最后一个返回值是额外的。例如，在if(5 == favorite_number)中更改顺序被认为是一种好习惯，因为您可能会错误地写出favorite_number = 5（赋值），这是有效的，这样您将很难找到一个错误。

如何使这个简单的程序返回而不关闭？

2 个答案: