我有一个文件,其中包含一些字符串,然后包含两个格式化的数组。看起来像这样
megabuck
Hello world
[58, 50, 42, 34, 26, 18, 10, 2,
61, 53, 45, 37, 29, 21, 13, 5,
63, 55, 47, 39, 31, 23, 15, 7]
[57, 49, 41, 33, 25, 17, 9,
1, 58, 50, 42, 34, 26, 18,
14, 6, 61, 53, 45, 37, 29,
21, 13, 5, 28, 20, 12, 4]
我事先不知道数组的 size 。我唯一知道的是数组[]
的定界符。什么是读取数组的一种优雅方法。
我是python的新手。
答案 0 :(得分:2)
使用正则表达式。 re.findall
例如:
import re
import ast
with open(filename) as infile:
data = infile.read()
for i in re.findall(r"(\[.*?\])", data, flags=re.S):
print(ast.literal_eval(i))
输出:
[58, 50, 42, 34, 26, 18, 10, 2, 61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7]
[57, 49, 41, 33, 25, 17, 9, 1, 58, 50, 42, 34, 26, 18, 14, 6, 61, 53, 45, 37, 29, 21, 13, 5, 28, 20, 12, 4]
答案 1 :(得分:0)
我不会称它为优雅,但是它可以工作
ars = """
megabuck
Hello world
[58, 50, 42, 34, 26, 18, 10, 2,
61, 53, 45, 37, 29, 21, 13, 5,
63, 55, 47, 39, 31, 23, 15, 7]
[57, 49, 41, 33, 25, 17, 9,
1, 58, 50, 42, 34, 26, 18,
14, 6, 61, 53, 45, 37, 29,
21, 13, 5, 28, 20, 12, 4]
"""
arrays = []
for a in ars.split("["):
if ']' in a:
arrays.append([i.strip() for i in a.replace("]",'').split(',')])