如何在SQL中获得以下结果

Question

我在下面提到了我的sql代码，

SELECT
    COUNT(id) FILTER (WHERE level_id = 1 AND applied_date::date = created_at::date) AS "D0_mobile_verification",
    COUNT(id) FILTER (WHERE level_id = 1 AND applied_date::date != created_at::date) AS "D+_mobile_verification",
    COUNT(id) FILTER (WHERE level_id = 4 AND applied_date::date = created_at::date) AS "D0_Docs",
    COUNT(id) FILTER (WHERE level_id = 4 AND applied_date::date != created_at::date) AS "D+_Docs",
    COUNT(id) FILTER (WHERE level_id = 9 AND applied_date::date = created_at::date) AS "D0_Esign",
    COUNT(id) FILTER (WHERE level_id = 9 AND applied_date::date != created_at::date) AS "D+_Esign"

FROM
    leads_table

结果类似于

enter image description here

但是我想要下面提到的结果。

enter image description here

你能帮我吗