循环打印多行(按预期),但只向文件写入一行

时间:2019-05-09 00:16:22

标签: python python-3.x loops

循环读取目录中的所有文本文件,并从每个文本文件的第一行打印值(按预期方式),但只向文件写入一行。

我已经尝试过使用for和while循环的几种循环变体,但是我认为我做错了。我之所以被淘汰是因为它可以打印正确的输出(几行),但是只写一行。

# this program reads the files in this directory and gets the value in the first line of each text file
# it groups them by the first two numbers of their filename

import glob

# get list of all text files in directory
path = "./*.txt"
txt_files = glob.glob(path)

# these are the groups I need to sort the results by
a1 = "10"
a2 = "20"
b1 = "30"
c1 = "40"

# list of files is in txt_files

for fileName in txt_files:

    # get the two digits from the filename to group the files
    device = fileName[2:4]

    # if the file name's first two digits (device) match the variable, open the file and get the value in the first line

    if device == a1:
        file = open(fileName)
        line = file.readline()
        # then, write that first line's value to the usage.txt file
        print(device + "_" + line)
        fileU = open("usage.txt", 'w')
        fileU.write(device + "_" + line + "\n")
        file.close()

    # if the file name's first two digits = 20, proceed

    elif device == a2:
        # open the text file and get the value of the first line
        file = open(fileName)
        line = file.readline()
        print(device + "_" + line)
        fileU = open("usage.txt", 'w')
        fileU.write(device + "_" + line + "\n")
        file.close()

    # if the file name's first two digits = 30, proceed

    elif device == b1:
        file = open(fileName)
        line = file.readline()
        print(device + "_" + line)
        fileU = open("usage.txt", 'w')
        fileU.write(device + "_" + line + "\n")
        file.close()

预期结果将是usage.txt,其显示的结果与控制台中打印的结果相同。

usage.txt只有一行:30_33

控制台将打印所有行:

  

10_36

     

10_36

     

20_58

     

20_0

     

20_58

     

30_33

     

30_33

     

以退出代码0结束的过程

2 个答案:

答案 0 :(得分:1)

您正在打开和截断文件,并以append打开:

由于每次循环都打开文件,并且没有使用a,因此每次循环都将其截断,因此每次循环都写入一个新的1行文件。

fileU = open("usage.txt", 'a')

答案 1 :(得分:1)

每次在循环中打开文件时,都会重新创建文件。您应该在循环之前将其打开一次。

with open("usage.txt", "w") as fileU:
    for fileName in txt_files:

        # get the two digits from the filename to group the files
        device = fileName[2:4]

        # if the file name's first two digits (device) match the variable, open the file and get the value in the first line

        if device == a1:
            file = open(fileName)
            line = file.readline()
            # then, write that first line's value to the usage.txt file
            print(device + "_" + line)
            fileU.write(device + "_" + line + "\n")
            file.close()

        # if the file name's first two digits = 20, proceed

        elif device == a2:
            # open the text file and get the value of the first line
            file = open(fileName)
            line = file.readline()
            print(device + "_" + line)
            fileU.write(device + "_" + line + "\n")
            file.close()

        # if the file name's first two digits = 30, proceed

        elif device == b1:
            file = open(fileName)
            line = file.readline()
            print(device + "_" + line)
            fileU.write(device + "_" + line + "\n")
            file.close()