Question

我有一个字符串数组

string[] my_array = {"5:five", "8:eight","4:four", "7:seven","1:one", "6:six"};

我希望有一个如下所示的输出字符串，以使值以升序连接

output_string = "onefourfivesixseveneight";

这是我的代码

string [] args = {"5:five", "8:eight","4:four", "7:seven","1:one", 
                              "6:six" ,"840"};
            string outputString = "";
           int lowest_divisor = 1;
           int dividend = Convert.ToInt32(args[args.Length - 1]);
           for(int i = 0; i<args.Length - 1; i++)
               {

               string[] pairs = args[i].Split(":");

               int divisor = Convert.ToInt32(pairs[0]);

               string pairString = pairs[1];

               if(i == 0)
               {

                   lowest_divisor = divisor;
                   outputString = pairString;
               }
               else if(divisor <= lowest_divisor)
               {
                   outputString = pairString + outputString;
                   lowest_divisor = divisor;
               }
               else if(divisor > lowest_divisor)
               {
                  outputString = outputString + pairString;


               }
    }

Answer 1

首先，我们只能将字符串限制为int：value格式

IEnumerable<string> validStrings = my_array.Where(x => x.Contains(':') && int.TryParse(x.Split(':')[0], out int test));

然后我们得到按整数值排序的列表

IEnumerable<string> orderedStrings = validStrings.OrderBy(x => int.Parse(x.Split(':')[0]));

然后我们可以将它们组合

string combined = string.Join("", orderedStrings.Select(x => x.Split(':')[1]));

Answer 2

我认为最简单的方法是使用linq。像这样：

string outputString = string.Join("", args.OrderBy(x => int.Parse(x.Split(':')[0])).Select(x => x.Split(':').Length > 1 ? x.Split(':')[1] : ""));

如果您不控制内容，则可以添加检查以确保其不会引发异常

Answer 3

与提供的linq解决方案相比，这有点冗长。

      SortedDictionary<int, string> dict = new SortedDictionary<int, string>();
      foreach (string s in my_array)
       {
            string[] splitArr=s.Split(':');
            dict.Add(Convert.ToInt32(splitArr[0]), splitArr[1]);
        }            

        StringBuilder sb = new StringBuilder();
        foreach (KeyValuePair<int, string> kvp in dict)
        {
            sb.Append(kvp.Value);
        }
        string final=sb.ToString();

在C＃中以升序对字符串数组进行排序

3 个答案: