我正在分析病历数据集,其中在4个不同时间点对患者进行了性传播感染筛查。数据管理器在每个时间段为每个STI的每位患者创建了一条线路。我要合并数据集,因此每个患者在每个时间点只有一行,列出了所有已诊断的STI。
我创建了新变量来捕获将在Dx变量下列出的每个STI,但是我无法弄清楚如何在同一数据集中合并数据,因此每个患者在每个时间点只有一个。
data dx;
set dx;
if dx='ANOGENITAL WARTS (CONDYLOMATA ACUMINATA)' then MRWarts=1;
if dx='CHLAMYDIA' then MRCHLAMYDIA=1;
if dx='DYSPLASIA (ANAL, CERVICAL, OR VAGINAL)' then MRDYSPLASIA=1;
if dx='GONORRHEA' then MRGONORRHEA=1;
if dx='HEPATITIS B (HBV)' then MRHEPB=1;
if dx='HUMAN PAPILLOMAVIRUSES (HPV)-ANY MANIFESTATION' then MRHPV=1;
if dx='PEDICULOSIS PUBIS' then MRPUBIS=1;
if dx='SYPHILIS' then MRSYPHILIS=1;
if dx='TRICHOMONAS VAGINALIS' then MRTRICHOMONAS=1;
run;
答案 0 :(得分:0)
获取图像中提供的样本数据集,您可以使用简单的转置以获得所需的结果。
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现在,此代码将创建除interval_round以外的所有变量,例如,假设-在第1轮中筛查了一名患者的艾滋病毒,在第2轮中筛查了疣,从技术上讲,它应该只有一行..那么,您将如何表示interval_round?